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Elena L [17]
3 years ago
7

Karlee says that 8 is a integer is she correct

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

Answer: yes she is correct

Step-by-step explanation: "An integer (from the Latin integer meaning "whole") is a number that can be written without a fractional component."

ExtremeBDS [4]3 years ago
6 0
Yes 8 is an integer
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EASY POINTSSS!!! <br> Do not round your answer. Type in just the number.<br><br> 35 is 25% of ?
oksano4ka [1.4K]

Step-by-step explanation:

\frac{25}{100} \times x = 35\\  \\  x = 35 \times  \frac{100}{25}  \\  \\x   = 35 \times 4\\\\x = 140

7 0
4 years ago
During the period of time that a local university takes phone-in registrations, calls come in
Zinaida [17]

Answer:

a) The expected number of calls in one hour is 30.

b) There is a 21.38% probability of three calls in five minutes.

c) There is an 8.2% probability of no calls in a five minute period.

Step-by-step explanation:

In problems that we only have the mean during a time period can be solved by the Poisson probability distribution.

Poisson probability distribution

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

a. What is the expected number of calls in one hour?

Calls come in at the rate of one each two minutes. There are 60 minutes in one hour. This means that the expected number of calls in one hour is 30.

b. What is the probability of three calls in five minutes?

Calls come in at the rate of one each two minutes. So in five minutes, 2.5 calls are expected, which means that \mu = 2.5. We want to find P(X = 3).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 3) = \frac{e^{-2.5}*(2.5)^{3}}{(3)!} = 0.2138

There is a 21.38% probability of three calls in five minutes.

c. What is the probability of no calls in a five-minute period?

This is P(X = 0) with \mu = 2.5.

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2.5}*(2.5)^{0}}{(0)!} = 0.0820

There is an 8.2% probability of no calls in a five minute period.

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3 years ago
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Step-by-step explanation:

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3 years ago
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A hockey player needs to shoot a puck 55 meters from his current location to his opponent's goal to score a goal. After the shot
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Answer:

The puck traveled 53.8 meters.

Step-by-step explanation:

Currently, the player is 55 meters away from the opponent's goal.

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