Answer:
a) 
b) 2012, 1049 stores. 2014, 1041 stores. c) Yes it is a downsizing company.
Step-by-step explanation:
a)
s=year | f(s) = number of stores per year
1 | 1078
4| 1067
s=1 in 2003
b) For 2012, s=9. For 2014, s=11
c) In deed. Since the function shows a decreasing amount of JC Penney stores. Maybe this is a downsizing from this company, progressively closing some stores.
For a binomial experiment in which success is defined to be a particular quality or attribute that interests us, with n=36 and p as 0.23, we can approximate p hat by a normal distribution.
Since n=36 , p=0.23 , thus q= 1-p = 1-0.23=0.77
therefore,
n*p= 36*0.23 =8.28>5
n*q = 36*0.77=27.22>5
and therefore, p hat can be approximated by a normal random variable, because n*p>5 and n*q>5.
The question is incomplete, a possible complete question is:
Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
Suppose n = 36 and p = 0.23. Can we approximate p hat by a normal distribution? Why? (Use 2 decimal places.)
n*p = ?
n*q = ?
Learn to know more about binomial experiments at
brainly.com/question/1580153
#SPJ4
Let's start with what we know:
Smaller canvas:
Length (
) = 3ft
Width (
) = 5ft
Larger canvas:
Length (
) = ?
Width (
) = 10ft
Since these are similar rectangles, we can cross-multiply to calculate the missing length. Here's that formula:
So let's plug it all in from above:
Now we cross multiply by multiplying the top-left by the bottom-right and vice versa:
Now divide each side by 5 to isolate
The 5s on the right cancel out, leaving us with:
So the length of the larger canvas is
6 ft
Step-by-step explanation:
Determine whether a number is a solution to an equation.
Substitute the number for the variable in the equation.
Simplify the expressions on both sides of the equation.
Determine whether the resulting equation is true. If it is true, the number is a solution. If it is not true, the number is not a solution.
Hoped that helped:P
Step-by-step explanation: This simple confidence interval calculator uses a Z statistic and sample mean (M) to generate an interval estimate of a population mean (μ).
Note: You should only use this calculator if (a) your sample size is 30 or greater; and/or (b) you know the population standard deviation (σ), and use this instead of your sample's standard deviation (an unusual situation). If your data does not meet these requirements, consider using the t statistic to generate a confidence interval.
where:
M = sample mean
Z = Z statistic determined by confidence level
sM = standard error = √(s2/n)
As you can see, to perform this calculation you need to know your sample mean, the number of items in your sample, and your sample's standard deviation (or population's standard deviation if your sample size is smaller than 30). (If you need to calculate mean and standard deviation from a set of raw scores, you can do so using our descriptive statistics tools.)
