Answer:
33 boxes.
Step-by-step explanation:
We have been given that a freight elevator can safely hold no more than 2000 pound. Weight of elevator operator is 165 pound. Weight of each box is 55 pound.
Let n be number of boxes. We will write an inequality as weight of elevator operator and weight of all boxes should be no more than 2000 pound.

Now we will solve our inequality to find number of boxes that could be moved safely at one time.



Therefore, 33 boxes can be moved safely at one time.
<h3>
Answer: 120 different ways</h3>
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Explanation:
There are...
- 6 ways to select the first place winner
- 5 ways to pick the second place winner
- 4 ways to pick the third place winner
We start with 6, and count down by 1 each time we fill up a slot. We stop once the third slot is filled or accounted for. The countdown is to ensure that we don't pick the same person twice. From here, multiply those values: 6*5*4 = 30*4 = 120
Interestingly, this is equal to 5! = 5*4*3*2*1 = 120 because the 3*2 becomes 6 and that *1 at the end doesn't affect things. Though usually results of permutation problems don't always end up like this. The order matters because a result like ABC is different from BAC, where A,B,C,D,E,F are the six school organizations.
As a slightly longer way to do the problem, you can use the nPr formula which is
where n = 6 and r = 3 in this case. The exclamation marks indicate factorial. If you go this route, you should find that one of the steps will involve 6*5*4.
Answer:
Range is 44
mean is 29.7
variance is 289.56
standard deviation is 17.016
Step-by-step explanation:
The data given as follows
3, 24, 30, 47, 43, 7, 47,13, 44, 39
Range = maximum - minimum
= 47 -3 = 44
mean =
= 297/10 = 29.7
variance =
= 289.56
SD =
= 17.016
The standard deviation of the given data is not a good measure as the range and standard deviation are far apart. The standard deviation gives how the given data is dispersed from the mean or expected value, while the range gives a rough idea of variability of the data.