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padilas [110]
4 years ago
13

Two objects, with masses m1 and m2, are originally a distance r apart. The gravitational force between them has magnitude F. The

second object has its mass changed to 2m2, and the distance is changed to r/4. What is the magnitude of the new gravitational force?
(A) 16F
(B) 32F
(C) F/16
(D) F/32
Physics
1 answer:
Romashka [77]4 years ago
6 0

Answer:

The magnitude of the new gravitational force becomes 32 times of the original force.

Explanation:

Two objects, with masses m₁ and m₂, are originally a distance r apart. the gravitational force between them is given by :

F=\dfrac{Gm_1m_2}{r^2}

If the second object has its mass changed to 2m₂ and the distance is changed to r/4, such that,

m_2'=2m_2 and r'=\dfrac{r}{4}

The new gravitational force is given by :

F'=G\dfrac{m_1m'_2}{r'^2}

F'=G\dfrac{m_1(2m_2)}{(r/4)^2}

F'=32\times G\dfrac{m_1m_2}{r^2}

F'=32F

So, the magnitude of the new gravitational force becomes 32 times of the original force. Hence, the correct option is (B) "32F".

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madam [21]

Answer:

Yes, a sled has inertia while sitting still.

Explanation:

From Newton's law of inertia, an object at rest will remain at rest unless it is acted upon by an external force. The reason the object will remain at rest unless an external force acts is because of inertia. Inertia means the resistance of an object to motion.

Thus, a sled hammer at rest will remain at rest unless it is acted upon by an external force. So we can conclude that it has Inertia.

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4 years ago
The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves pa
tensa zangetsu [6.8K]

Complete question:

Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?

Part B: What is the momentum of a proton traveling at 0.62 c ?

Answer

a)Who would have aged less=The Captain would have aged less

b) p=3.96*10^{-19}kgm/s

Explanation:

From the question we are told that

Length measured by captain l_c=50m

Speed of rocket past tje space dock V=0.5c

Length measured by space-dock personnel l_c=43.3m

a)

Generally time moves slower when moving at speed of light, due to time dilation or variation.

Who would have aged less=The Captain would have aged less

b)

Generally the equation for Relativistic Momentum  is mathematically given as

p=\frac{m*v}{1 - v^2/c^2}

p=\frac{1.67*10^2-27*0.62*3.0*10^8)}{\sqrt{ 1 -0.6^2}}

p=3.96*10^{-19}kgm/s

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A certain first-order reaction is 58% complete in 95 s. What are the values of the rate constant and the half-life for this proc
guajiro [1.7K]

Answer:

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

Explanation:

Expression for rate law for first order kinetics is given by:

a_o=a\times e^{-kt}

where,

k = rate constant  

t = age of sample

a_o = let initial amount of the reactant  

a = amount left after decay process  

We have :

a_o=x

a=58\%\times x=0.58x

t = 95 s

0.58x=x\times e^{-k\times 95 s}

\k= 0.005734 s^{-1}

Half life is given by for first order kinetics::

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{0.005734 s^{-1}}=120.86 s

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

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If the frequencies of two component waves are 24 Hz and 20 Hz, they should produce _______ beats
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