In the photoelectric effect, the energy given by the incoming photon is used partially to extract the electron from the metal (work function) and the rest is converted into kinetic energy of the electron:

where
hf is the energy of the photon, with h being the Planck constant and f the frequency of the photon

is the work function
K is the kinetic energy of the electron
When K=0, we have the minimum energy required to extract the electron from the metal, so the equation becomes

(1)
If we convert the work function of gold into Joules:

We can re-arrange eq.(1) to find the minimum energy of the photon:
To solve this problem it is necessary to apply the concepts related to the conservation of energy, specifically the potential elastic energy against the kinetic energy of the body.
By definition this could be described as


Where
k = Spring constant
x = Displacement
m = mass
v = Velocity
This point is basically telling us that all the energy in charge of compressing the spring is transformed into the energy that allows the 'impulse' seen in terms of body speed.
If we rearrange the equation to find v we have

Our values are given as



Replacing at our equation we have then,



Therefore he speed of the car before impact, assuming no energy is lost in the collision with the wall is 2.37m/s
First we can calculate the average speed v in km/h by the equation v=s/t where s is the distance traveled and t is the time:
First we turn time into seconds and divide by 3600 to get time t in hours is:
t=13*3600 s + 4*60 s + 58 s= 47098 s and that is:
t=47098s/3600s=13.08278 hours
So v=1633.8/13.08278=124.88 km/h
To get speed in m/s we simply turn kilometers into meters and hours into seconds:
s=1633.8 km *1000 = 1633800 m
t=13*3600s + 4*60 s + 58 s=46800 s + 240 s + 58 s=47098 s
v=s/t=1633800/47098=34.67 m/s
So average speed in km/h is v=124.88 km/h and in m/s is v= 34.67 m/s.
WHTATATATTSSHSJSD ....... 22
Sorry for the inconvenience I jus need the 5 points