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padilas [110]
4 years ago
13

Two objects, with masses m1 and m2, are originally a distance r apart. The gravitational force between them has magnitude F. The

second object has its mass changed to 2m2, and the distance is changed to r/4. What is the magnitude of the new gravitational force?
(A) 16F
(B) 32F
(C) F/16
(D) F/32
Physics
1 answer:
Romashka [77]4 years ago
6 0

Answer:

The magnitude of the new gravitational force becomes 32 times of the original force.

Explanation:

Two objects, with masses m₁ and m₂, are originally a distance r apart. the gravitational force between them is given by :

F=\dfrac{Gm_1m_2}{r^2}

If the second object has its mass changed to 2m₂ and the distance is changed to r/4, such that,

m_2'=2m_2 and r'=\dfrac{r}{4}

The new gravitational force is given by :

F'=G\dfrac{m_1m'_2}{r'^2}

F'=G\dfrac{m_1(2m_2)}{(r/4)^2}

F'=32\times G\dfrac{m_1m_2}{r^2}

F'=32F

So, the magnitude of the new gravitational force becomes 32 times of the original force. Hence, the correct option is (B) "32F".

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In the photoelectric effect, the energy given by the incoming photon is used partially to extract the electron from the metal (work function) and the rest is converted into kinetic energy of the electron:
hf= \phi + K
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When K=0, we have the minimum energy required to extract the electron from the metal, so the equation becomes
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If we convert the work function of gold into Joules:
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We can re-arrange eq.(1) to find the minimum energy of the photon:
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4 years ago
An automobile having a mass of 1,000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with cons
Nady [450]

To solve this problem it is necessary to apply the concepts related to the conservation of energy, specifically the potential elastic energy against the kinetic energy of the body.

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If we rearrange the equation to find v we have

v = \sqrt{\frac{kx^2}{m}}

Our values are given as

m = 1000kg

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Replacing at our equation we have then,

v = \sqrt{\frac{kx^2}{m}}

v = \sqrt{\frac{(5.75*10^6)(3.12*10^{-2})^2}{1000}}

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3 years ago
On may 26, 1934, a streamlined, stainless steel diesel train called the zephyr set the world’s nonstop long-distance speed recor
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First we turn time into seconds and divide by 3600 to get time t in hours is:

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t=47098s/3600s=13.08278 hours

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To get speed in m/s we simply turn kilometers into meters and hours into seconds:

s=1633.8 km *1000 = 1633800 m 

t=13*3600s + 4*60 s + 58 s=46800 s + 240 s + 58 s=47098 s

v=s/t=1633800/47098=34.67 m/s

So average speed in km/h is v=124.88 km/h and in m/s is v= 34.67 m/s. 


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