Question

Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?

Answer 1

Y=(x+3)^2-6 Hope This Helps

Answer 2

Answer:

$f(x)=(x+3)^{2}-6$

Step-by-step explanation:

we have

$f(x)=x^{2} +6x+3$

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) ------> is the vertex of the parabola

Convert the function into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-3=x^{2} +6x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-3+9=x^{2} +6x+9$

$f(x)+6=x^{2} +6x+9$

Rewrite as perfect squares

$f(x)+6=(x+3)^{2}$

$f(x)=(x+3)^{2}-6$ -----> function in vertex form