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4 years ago

The Sum of a number y and -3 is -8

Mathematics

1 answer:

Firlakuza [10]4 years ago

8 0

Answer:

y=-5

Step-by-step explanation:

y-3=-8

y=-8+3

y=-5

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Please help me solve this........ (x+1)(x^2-x+1)

maksim [4K]

4 0

4 years ago

X-3/-7 ≤ 8<br> Solve the inequality.

Veronika [31]

Answer:

x is less than or equal to 59/7

Step-by-step explanation:

8 0

3 years ago

Cone is formed from 3200 ft of gravel, if the height of the cone is 24 ft what is the radius in feet of the base of the cone

Lesechka [4]

Question :

Cone is formed from 3200 ft³ of gravel, if the height of the cone is 24 ft what is the radius in feet of the base of the cone

Answer:

11.3 feet

Step-by-step explanation:

The volume of a cone = πr²h/3

We are asked to find the radius

The formula is given as:

r = √3V/πh

V = 3200 ft³

h = 24 ft

r = √3 × 2400/π × 24

r = 11.28379 ft

Approximately = 11.3 ft

The radius in feet = 11.3 ft

5 0

3 years ago

Choose the expression that represents “three less than seven times a number.

olga nikolaevna [1]

7x-3 should be the answer

6 0

3 years ago

Read 2 more answers

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago