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3 years ago

when you multiply a number by itself then multiply that number by another number and it equals 80 what are the 2 numbers?

Mathematics

2 answers:

Stells [14]3 years ago

6 0

x^2 * y = 80

4^2 * 5 = 80

x = 4 and y = 5 will fit this equation.

sasho [114]3 years ago

3 0

4 and 5
(4)(4)=16 then (16)(5)=80

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The length of a log of wood is 90 in. How many cuts do you need to make to obtain

Ilia_Sergeevich [38]

The greatest number of pieces will be 12 where each piece will have a different length and the length of each piece is a whole number, in inches and the remaining piece length will be 12 in(90 - 78).

<h3>What is a sequence?</h3>

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

The total length of the wood = 90 in

We have to cut it into the greatest number of pieces, where each piece will have a different length and the length of each piece is a whole number, in inches.

We can cut it like:

1 in, 2 in, 3 in, 4 in, and so on

The above shows the arithmetic sequence,

The sum of the n natural number is given by:

$\rm S_n = \dfrac{n(n+1)}{2}$

$\rm 90 = \dfrac{n(n+1)}{2}$

After solving, we will get a quadratic equation:

n² + n -180 = 0

After solving, we will get:

n = 12.92 and n = -13.92(term can not be negative)

n = 12 (taking whole number)

Thus, the greatest number of pieces will be 12 where each piece will have a different length and the length of each piece is a whole number, in inches and the remaining piece length will be 12 in(90 - 78).

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brainly.com/question/21961097

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2 years ago

How does technology affect the economy

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Answer:

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i didn't know if you wanted the positive or negatives affects

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2 years ago

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3 years ago

Consider a melody to be 7 notes from a single piano octave, where 2 of the notes are white key notes and 5 are black key notes.

igor_vitrenko [27]

Answer:

35,829,630 melodies

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There are 12 half-steps in an octave and therefore $12^7$ arrangements of 7 notes if there were no stipulations.

Using complimentary counting, subtract the inadmissible arrangements from $12^7$ to get the number of admissible arrangements.

$\displaystyle \_\_ \:B_1\_\_ \:B_2\_\_ \:B_3\_\_ \:B_4\_\_ \:B_5\_\_$

$B_1$ can be any note, giving us 12 options. Whatever note we choose, $B_2, B_{...}$ must match it, yielding $12\cdot 1\cdot 1\cdot 1\cdot 1=12$ . For the remaining two white key notes, $W_1$ and $W_2$ , we have 11 options for each (they can be anything but the note we chose for the black keys).

There are three possible arrangements of white key groups and black key groups that are inadmissible:

$WWBBBBB\\WBBBBBW\\BBBBBWW$

White key notes can be different, so a distinct arrangement of them will be considered a distinct melody. With 11 notes to choose from per white key, the number of ways to inadmissibly arrange the white keys is $\displaystyle\frac{11\cdot 11}{2!}$ .

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$\displaystyle 12^7-3\left(\frac{12\cdot 11\cdot 11}{2!}\right)=\boxed{35,829,630}$

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