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yuradex [85]
3 years ago
7

Simplify $\frac{k-3}{2} + 3k+1+\frac{3k+1}{2}$

Mathematics
1 answer:
podryga [215]3 years ago
8 0
\frac{k-3}{2}+3k+1+\frac{3k+1}{2}\\\frac{k-3}{2}+\frac{3k}{1}(\frac{2}{2})+\frac{1}{1}(\frac{2}{2})+\frac{3k+1}{2}\\\frac{k-3}{2}+\frac{3k*2}{2}+\frac{1*2}{2}+\frac{3k+1}{2}\\\frac{(k-3)+6k+2+(3k+1)}{2}\\\frac{10k+0}{2}\\\\5k

Thus, the expression simplifies to become 5k.
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