The answer is 2 hours and 15 minutes
9514 1404 393
Answer:
119 4/7
Step-by-step explanation:
The perimeter is the sum of side lengths.
10 1/7 + 12 2/7 + 15 3/14 + 24 1/14 + 12 2/7 + 10 1/7 + 35 3/7
= (10 + 12 + 15 + 24 + 12 + 10 + 35) + (1 + 2 + 2 + 1 + 3)/7 + (3 + 1)/14
= 118 + 9/7 + 4/14
= 118 + 1 2/7 + 2/7
= 119 4/7 . . . . perimeter of the figure
Remember
you can do anyting to an equaiton as long as you do it to both sidess
distributive property
a(b+c)=ab+ac
commutativ property
a+b=b+a
distribute
3(4x-2)=12x-6
12x-6=9+2x+5
add 6 both sides
12x+6-6=9+6+5+2x
12x+0=20+2x
minus 2x
10x=20
divide 10
x=2
So 5
then 5 times 5
then 5 times 5 times 5
so it seems that for x rounds, there will be 5^x
A: 4 rounds so 5^4=625 photos
B. see how many times 5 goes into 78125. the answer is 7 so 7 rounds
C. 1 million=1,000,000 so try big numbers
5^10=9,765,625 too big
5^9=1,9,53,125 too big
5^8=390625 too small
the minimum is 5^9 or 9 rounds
A:4
B:7
C:9
Answer:
13.89% of students are willing to report cheating by other students.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 180
Number of students who reported cheating, x = 25
We have to find the proportion of the students are willing to report cheating by other students.
Proportion of students can be calculate as

Thus, 13.89% of students are willing to report cheating by other students.