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Svetlanka [38]
4 years ago
9

Which factor 25^2+40x+16 and 25x^2-16 have in common

Mathematics
1 answer:
Goryan [66]4 years ago
6 0

25^2+40x+16

= (5x + 4)(5x + 4)


and

25x^2-16

= (5x)^2 -(4)^2

= (5x + 4)(5x - 4)

Both have same factor (5x + 4)

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D.

4.33 \times  {10}^{6}

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I need help with this <br>​
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Step-by-step explanation:

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a pair of jeans originally cost $140 and are now on sale for 65% off. what is the sale price of the jeans
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Answer:

$49

Step-by-step explanation:

<u><em>Method 1</em></u><u><em>:</em></u>

100% - 65% = 35%

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<u><em>Method 2</em></u><u><em>:</em></u>

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3 0
3 years ago
An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe
Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%

Taking p and N as common factors, we get:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%

Then we get:

\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%

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