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Svetlanka [38]
4 years ago
9

Which factor 25^2+40x+16 and 25x^2-16 have in common

Mathematics
1 answer:
Goryan [66]4 years ago
6 0

25^2+40x+16

= (5x + 4)(5x + 4)


and

25x^2-16

= (5x)^2 -(4)^2

= (5x + 4)(5x - 4)

Both have same factor (5x + 4)

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Karen's dance class starts at 4:30 PM and ends at 6:15 PM how long is her dance class
Ede4ka [16]
The answer is 2 hours and 15 minutes 

3 0
3 years ago
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151 241<br> 12 12<br> 102<br> 101<br> 35<br> Perimeter<br> ?<br> Simplify your answer completely
Nataliya [291]

9514 1404 393

Answer:

  119 4/7

Step-by-step explanation:

The perimeter is the sum of side lengths.

  10 1/7 + 12 2/7 + 15 3/14 + 24 1/14 + 12 2/7 + 10 1/7 + 35 3/7

  = (10 + 12 + 15 + 24 + 12 + 10 + 35) + (1 + 2 + 2 + 1 + 3)/7 + (3 + 1)/14

  = 118 + 9/7 + 4/14

  = 118 + 1 2/7 + 2/7

  = 119 4/7 . . . . perimeter of the figure

8 0
3 years ago
Solve and SHOW YOUR WORK for the equation 3(4x – 2) = 9 + 2x + 5
enot [183]
Remember
you can do anyting to an equaiton as long as you do it to both sidess

distributive property
a(b+c)=ab+ac
commutativ property
a+b=b+a

distribute
3(4x-2)=12x-6

12x-6=9+2x+5
add 6 both sides
12x+6-6=9+6+5+2x
12x+0=20+2x
minus 2x
10x=20
divide 10
x=2
3 0
4 years ago
Read 2 more answers
Tamara texted a photo of a dolphin to 5 friends. She asked each of her 5 friends to text the photo to 5 more friends. The photo
Andreyy89
So 5
then 5 times 5
then 5 times 5 times 5
so it seems that for x rounds, there will be 5^x 

A: 4 rounds so 5^4=625 photos
B. see how many times 5 goes into 78125. the answer is 7 so 7 rounds
C. 1 million=1,000,000 so try big numbers
5^10=9,765,625 too big
5^9=1,9,53,125 too big
5^8=390625 too small
the minimum is 5^9 or 9 rounds

A:4
B:7
C:9

4 0
3 years ago
What proportion of students are willing to report cheating by other students? A project put this question to an SRS of 180 under
krok68 [10]

Answer:

13.89% of students are willing to report cheating by other students.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 180

Number of students who reported cheating, x = 25

We have to find the proportion of the students are willing to report cheating by other students.

Proportion of students can be calculate as

p = \dfrac{x}{n} = \dfrac{25}{180} = 0.1389\\\\\p = 0.1389\times 100\5\\p = 13.89\%

Thus, 13.89% of students are willing to report cheating by other students.

8 0
3 years ago
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