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STatiana [176]
3 years ago
12

On a test, 74% of the questions are answered correctly. If 111 questions are correct, how many questions are on the test?

Mathematics
2 answers:
Mashcka [7]3 years ago
5 0

Answer:

150

Step-by-step explanation:

You have to divide the correct answers (111) by the total amount of questions (x) in order to find the 74% (0.74)

Phantasy [73]3 years ago
5 0

Answer: there are 150 questions in the test.

Step-by-step explanation:

Let x represent the total number of questions in the test.

On a test, 74% of the questions are answered correctly. This means that the number of questions that were answered correctly is

74/100 × x = 0.74 × x = 0.74x

If 111 questions are correct, it means that

0.74x = 111

Dividing the left hand side and the right hand side of the equation by 0.74, it becomes

0.74x/0.74 = 111/0.74

x = 150

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Answer:

Given:

For battery k(sample 1):

Sample size, n = 75

Sample mean, X' = 9.41

Standard deviation = 0.723

Mean u1 =???

For battery Q(sample 2):

Sample size, n = 49

Sample mean, X' = 9.69

Standard deviation = 0.257

Mean u2 =???

Significance level = 0.05

1) The null and alternative hypotheses, will be given as:

H0 : u1 - u2 = 0

H1 : u1 - u2 ≠ 0

2) This is a two tailed test.

For the test statistic, we have :

Z_o = \frac{X'_1 - X'_2}{\sqrt{\frac{(\sigma_1)^2}{n_1} + \frac{(\sigma_2)^2}{n_2}}}

= \frac{9.41 - 9.69}{\sqrt{\frac{(0.723)^2}{75} + \frac{(0.257)^2}{49}}} = - 3.018

≈ 3.02

The Zo = - 3.02

3) For the p value, using excel, we have:

2 * P(Z > (-3.018))

= 2 * NORMDIST (-3.018, 0, 1, true)

= 0.00254

For critical value:

Zcritical = Za/2 = 0.05/2

Zcritical = 0.025

We have alternative hypothesis,

H1 : u1 - u2 ≠ 0.

Therefore we reject null hypothesis H0 if Zo > Zcritical

4) We reject null hypothesis H0 if Zo > Zcritical. At 0.05 level of significance, there is not enough evidence to conclude that mean u1 and mean u2 are different.

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