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Dafna1 [17]
2 years ago
7

A field is a rectangle with a perimeter of 1040 feet. The length is 300 feet more than the width. Find the width and the length

of the rectangular field. What is the width of the rectangular field?
Mathematics
1 answer:
Ratling [72]2 years ago
4 0

Answer:

Width = 110 ft

Step-by-step explanation:

width = x

length = x + 300

To find the width, we use the formula for perimeter, substituting 1040 for perimeter, x + 300 for length, and x for width:

P=2(l+w)\\\\1040=2[(x+300)+x]

Combine like terms inside the brackets:

1040=2(2x+300)

Distribute the 2 within the parentheses:

1040=4x+600

Subtract 600 from both sides:

440=4x

Divide both sides by 4:

110=x

Therefore, the width is 110 ft and the length is 410 ft. To verify, we can check that the perimeter equals 1,040 ft.

P=2(l+w)\\P=2(410+110)\\P=2(520)\\P=1040\\Check.

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Answer:

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First we convert inequality equation into equality equation to find the solution of the given system of inequality equation.

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(30,10) is the intersect point of two equation.

Put x=0 in equation (3)

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Hence, the value of x lies between 20 and 40 and value of y lies between -20 and 10.

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