Answer:
the answer is 216 m²
Step-by-step explanation:
3 time 6 equals 18
18 times 2 is 36
3 times 10 is 30
30 times 2 is 60
6 times 10 is 60
60 times 2 is 120
120+60+36=216
I think you meant to say
![\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bt%5Cto2%7D%5Cfrac%7Bt%5E4-6%7D%7B2t%5E2-3t%2B7%7D)
(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:
![\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bt%5Cto2%7D%20%5Cfrac%7Bt%5E4%20-%206%7D%7B2t%5E2%20-%203t%20%2B%207%7D%20%3D%20%5Cfrac%7B%5Cdisplaystyle%20%5Clim_%7Bt%5Cto2%7D%28t%5E4-6%29%7D%7B%5Cdisplaystyle%20%5Clim_%7Bt%5Cto2%7D%282t%5E2-3t%2B7%29%7D)
Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:
![\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bt%5Cto2%7D%20%5Cfrac%7Bt%5E4%20-%206%7D%7B2t%5E2%20-%203t%20%2B%207%7D%20%3D%20%5Cfrac%7B%5Cdisplaystyle%20%5Clim_%7Bt%5Cto2%7D%28t%5E4-6%29%7D%7B%5Cdisplaystyle%20%5Clim_%7Bt%5Cto2%7D%282t%5E2-3t%2B7%29%7D%20%3D%20%5Cfrac%7B2%5E4-6%7D%7B2%5Ccdot2%5E2-3%5Ccdot2%2B7%7D%20%3D%20%5Cboxed%7B%5Cfrac%7B10%7D9%7D)
Answer:
![n=50](https://tex.z-dn.net/?f=n%3D50)
Step-by-step explanation:
Based on the given conditions, formulate
% × ![n=8](https://tex.z-dn.net/?f=n%3D8)
Multiply the monomials: 16% * n = 8
Reduce the greatest common factor on both sides of the equation: n = 50
ANSWER: n = 50