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Arada [10]
3 years ago
11

Which operation would you do second in the following problem?

Mathematics
2 answers:
eimsori [14]3 years ago
7 0

it's addition i looked it up

Advocard [28]3 years ago
4 0

Subtraction because you need to get rid of the parentheses first then add. Because first is parenthesis/division in the order of operations.

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The weight of a population of yeast is given by a differentiable function y, where y(t) is measured in grams and t is measured i
Deffense [45]

Answer:

b) y = 120e^{t/5}

Step-by-step explanation:

given that the weight of a population of yeast is given by a differentiable function y, where y(t) is measured in grams and t is measured in days. The weight of the yeast population increases according to the equation

\frac{dy}{dt} =ky for a constant k.

Separate the variables and integrate

ln y=k t +C\\y = Ae^{kt}

Use the fact when t=0 y = 120

120 = A

y = 120e^{kt}

When t =1, rate of grwoth is 24 gms.

i.e. 144 = 120e^{k*1}\\k = ln 144/120 = 0.1823~0.2

Hence option b i.e.

y = 120e^{t/5}

6 0
3 years ago
The values that are solutions of x2 + 20 =12x
vodomira [7]
Is the first value x^2?
5 0
3 years ago
Write the equation of a line that is perpendicular to y = 7/5 x + 6 y= 5/7and that passes through the point ( 2 , − 6 )
Margarita [4]

<u>Answer</u>:

Equation of a line perpendicular toy = \frac{7}{5x} + 6 and passes through the point ( 2 , − 6 ) is   5x – 7y = 4.

<u>Explanation</u>:

Need to write equation of line perpendicular  to y = 7/5x + 6 and passes through the point ( 2 , − 6 )

Generic slope intercept form of a line is given by y = mx + c , where m = slope of the line.

On comparing the given slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line y = \frac{7}{5}x + 6, slope m = 7/5

Product of slope of perpendicular line is -1 .

Let say slope of required line perpendicular to y = 7/5x + 6 is represented by m1  

And as Product of slope of perpendicular line is -1 .

=> m \times m1 = -1

=>\frac{7}{5}\times m1 = -1

=>m1 = \frac{-5}{7}

so now we  need to find the equation of a line whose slope is \frac{-5}{7} and passing through (2 , -6).

Equation of line passing through (x1 , y1)  and having slope of m is given by  

(y – y1) = m (x – x1)

In our case x1 = 2 and  y1 = -6  and m = -5/7  

Substituting the values in equation of line we get

=>  (y-(-6)) = \frac{-5}{7} (x-2)

=>y +6= \frac{-5}{7} x + \frac{10}{7}

=> 7(y +6) = -5x +10

=> 5x – 7y = 10 – 6

=> 5x – 7y = 4  

Hence equation of a line perpendicular toy = \frac{7}{5x} + 6  and passes through the point ( 2 , − 6 ) is  

5x – 7y = 4.

8 0
4 years ago
Y Given: 6x + 7 = 8x - 17; Prove: x = 12
Molodets [167]

REASONS:-

1ST STEP

6x + 7 = 8x - 17

GIVEN LHS = RHS

2ND STEP

7 = 2x - 17

Bez +ve 6x when move to another side will change to -ve so it reduces 8x to 2x

3RD STEP

24 = 2x

Bez -ve 17 when move to another side will change to +ve so it increases 7 to 24

4TH STEP

12 = x

Bez 2 in multiplication when move to another side will change to division so it reduces 24 to 12

5TH STEP

x = 12

it the answer we obtained after solving

6 0
3 years ago
Which is expression is equivalent to 4b
GalinKa [24]

Answer: b(4) or 4(b)

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
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