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3 years ago

Find solutions to the linear equation y=−10x+30.

1 answer:

4 0

Answer: x=-y-30/10

1) subtract 30 from both sides

y−30=−10x

2) divide both sides by -10

-y-30/10=x

3) switch sides

x=-y-30/10

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180 - 151 = 29

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3 years ago

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Lera25 [3.4K]

I got you sis :)

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3 years ago

Scores on an English test are normally distributed with a mean of 31.5 and a standard deviation of 7.3. Find the score that sepa

vladimir1956 [14]

If $X$ is a random variable representing test scores, then the 41st percentile is the score $x$ such that $P(X\le x)=0.41$ . Transform $X$ to the random variable $Z$ that follows the standard normal distribution via $X=31.5+7.3Z$ :

$P(X\le x)=P\left(\dfrac{X-31.5}{7.3}\le\dfrac{x-31.5}{7.3}\right)=P\left(Z\le\dfrac{x-31.5}{7.3}\right)=0.41$

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4 years ago