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3 years ago

I WILL GIVE BRAINLYYYY PLS HELPPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

romanna [79]3 years ago

5 0

Answer:

The Average rate of the first plane is 560 mph

Step-by-step explanation:

x = first plane's average rate (in mph)

x−108 = second plane's average rate (in mph)

First planes total distance = 2.25x

Second planes total distance = 1.25(x−108)

2.25x + 1.25(x−108) = 1825

x = 560

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One cup of sweetened condensed milk weighs 10.8 ounces.How many whole cups of sweetened condensed milk can you get from a 15-po

ElenaW [278]

Answer:

162 ounces

Step-by-step explanation:

conversion problem

1 cup = 10.8 ounces

15*10.8=162

5 0

2 years ago

Your grade before taking the final exam is 493pts out of 510 possible points. The final exam is worth 100 points. How many point

Scorpion4ik [409]

Answer:

You need 75 points.

Step-by-step explanation:

Giving the following information:

Total number of points= 510 + 100= 610 (100%)

Actual number of points= 493

First, we need to determine the number of points required to reach 93%:

Points required= 610*0.93

Points required= 567.3 = 568

Now, the points needed in the final exam:

Difference of points= 568 - 493

Difference of points= 75 points

You need 75 points.

4 0

2 years ago

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

5 0

3 years ago

Find the value of x in the triangle shown below. 6 10

Jobisdone [24]

Answer:

Step-by-step explanation:

The value of x is 50 degrees

bcoz it is isosceles triangle

so two angles are equal

so value of x is 50

I hope this will help u

3 0

2 years ago

Read 2 more answers

an angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5cm long. A second side of the

rodikova [14]

There is a not so well-known theorem that solves this problem.

The theorem is stated as follows:
"Each angle bisector of a triangle divides the opposite side into segments proportional in length to the adjacent sides" (Coxeter & Greitzer)

This means that for a triangle ABC, where angle A has a bisector AD such that D is on the side BC, then
BD/DC=AB/AC

Here either
BD/DC=6/5=AB/AC, where AB=6.9,
then we solve for AC=AB*5/6=5.75,

or

BD/DC=6/5=AB/AC, where AC=6.9,
then we solve for AB=AC*6/5=8.28

Hence, the longest and shortest possible lengths of the third side are
8.28 and 5.75 units respectively.

4 0

3 years ago

Read 2 more answers