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kenny6666 [7]
3 years ago
10

How do I write an inequality for 6x+8>2

Mathematics
1 answer:
Hatshy [7]3 years ago
7 0

Answer:

The inequality is x>-1

Step-by-step explanation:

Given:

The inequality to solve is given as:

6x+8>2

Now, in order to solve it for 'x', we need to isolate 'x' on one side of the inequality.

<em>Adding -8 on both sides, we get:</em>

6x+8-8>2-8\\\\6x>-6

<em>Dividing both sides by 6, we get:</em>

\frac{6x}{6}>\frac{-6}{6}\\\\x>-1

Therefore, the inequality for 'x' is given as:

x>-1

So, 'x' include all the values that are greater than -1.

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Step-by-step explanation:

Hope this helps!

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Step-by-step explanation:

When doing these types of problems I like to do this.

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Find the area of the isosceles triangle. please help thanks
fiasKO [112]

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2                      Substitute for b^2 = h^2

24^2 + h^2 = 51^2                   Expand 24^2 and 51^2

576 + h^2 = 2601                    Subtract 576 from both sides

h^2 = 2601 - 576

h^2 = 2025                              Take the square root of both sides

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Area

Area = 1/2 b * h

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Remark

Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

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