Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:
I'm going to solve 
for x using the quadratic formula:
Let's see if uv=u+v holds.
Keep in mind you are multiplying conjugates:
Let's see what u+v is now:
We have confirmed uv=u+v for k=2.
We know that
<span>63 2/3 feet----------------> (63*3+2)/3---------> 191/3 ft
</span>
1 ft-----------------> 12 in
191/3 ft----------------> X in
X=(191/3)*12------------> X=764 in
the answer is 764 in
Answer:
Step-by-step explanation:
Problem:
The possible values of x in the equation (60)x = 1;
Solution:
Such a problem like this in which the highest power of the unknown is 1 will have just one solution.
60x = 1
To solve this, we take the multiplicative inverse of 60;
the multiplicative inverse of 60 =
Use this inverse to multiply both sides of the expression;
60x = 1 x
x =
Step-by-step explanation:
EF is a segment so it's a line with the end points as E and F. Line RS bisects(cuts in half) line EF. Then where the two lines meet is where A is.
Hope this helped.
Answer:
Then it would be 4n squared + 21
Step-by-step explanation:
