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patriot [66]
3 years ago
13

Can someone explain to me how this is done

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

i think its 1/5

Step-by-step explanation:

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Which describes the association between variables x and y ?
e-lub [12.9K]
A strong positive

The plot has a positive slope and very close together pattern, so I would say a strong positive
8 0
4 years ago
What is the slope of the line that goes through the points (12,-18) (-15,-18)
AnnZ [28]

Hi!

Step-by-step explanation:

SLOPE=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}

\frac{(-18)-(-18)}{(-15)-12}=\frac{0}{-27}=0

<u><em>Slope is 0.</em></u>

<u><em>The answer is 0.</em></u>

Hope this helps!

Have a nice day! :)

:D

-Charlie

Thank you!

4 0
3 years ago
Find each missing angle measure<br> 3=<br> 4=
Yanka [14]

Answer:

<4 = 88

<3 = 92

Step-by-step explanation:

The sum of the angles of a triangle is 180

<4 + 45+ 47 = 180

<4 + 92 = 180

< 4 = 180-92

<4 = 88

We know the <3 and <4 form a line

<3 + <4 = 180

<3 + 88 = 180

< 3 = 180-88

<3 = 92

6 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Find the measure of a 6.<br> 102<br> 78<br> 46 = [?]
Rom4ik [11]

Answer:

102°

Step-by-step explanation:

They're still corresponding angles... have you read any of these explanations?...

6 0
3 years ago
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