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telo118 [61]
3 years ago
12

I would appreciate if this was answered ASAP please

Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0

i think its c.

i found out why:

A proposition of the form “if p then q” or “p implies q”, represented “p → q” is called a conditional proposition. ... The proposition p is called hypothesis or antecedent, and the proposition q is the conclusion or consequent. Note that p → q is true always except when p is true and q is false

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Mike made a 9-inch sub sandwich. He needs to cut it into 2/3 inch pieces. How many pieces will he be able to cut?
Igoryamba

Answer:

13 pieces

Step-by-step explanation:

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Please help me with this math problem!! Will give brainliest!! :)
aleksandrvk [35]

Answer:

-3

Step-by-step explanation:

(fg)(-1) is just f(-1) * g(-1). From the graph on the left, we can see that f(-1) is 1, since (-1,1) is on the graph. From the graph on the tight, we can see that g(-1) is -3, since (-1,-3) is on the graph. Now, we just have to multiply 1 and -3: 1*-3 = -3

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2 years ago
Solve for x <br><br> Please show your work <br><br> Thank you
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6-4=2
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5-2=3
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That is the answer, sorry if i didn't explain it well<span />
6 0
3 years ago
Components of a certain type are shipped to a supplier in batches of ten. Suppose that 50% of all such batches contain no defect
ad-work [718]

Answer:

a) P (0 defective component) = 0.5

   P( 1 defective component ) = 0.35

    P( 2 defective component ) = 0.15

b) P( 0 ) = 0

   p ( 1 ) =  1

   p ( 2 ) = 0.33

Step-by-step explanation:

p( no defective ) = 0.5

p( 1 is defective ) = 0.35

p( 2 is defective ) = 0.15

Given that 2 components are selected at random

<u>a) Given that neither component is defective </u>

Probability of 0 defective component = 0.5

P( 1 defective component ) = 0.35

P( 2 defective component ) = 0.15

<u>b) Given that one of the two tested component is defective </u>

P( 0 defective ) = 0

P( 1 defective ) = P ( \frac{x=1}{x\geq 1} ) = p( x = 1 ) / 1 - P ( x = 0 )

                                        = ( 0.5 )^1 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^1

                                        = 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 =  1

p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )

                         = ( 0.5 )^2 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^2

                         = 0.25 / 0.75 = 0.33

<u />

5 0
3 years ago
How i can prove the proofs?
Marianna [84]
You can prove the proofs by showing your work to prove the proofs.
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