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yawa3891 [41]
4 years ago
12

Using the Pythagorean Theorem

Advanced Placement (AP)
2 answers:
Lina20 [59]4 years ago
7 0

Answer:

Yes, the sum of the two smaller squares equals the  largest square

Explanation:

See the picture attached. There are 3 squares with areas: a², b² and c². The  Pythagorean Theorem states:

c² = a² + b²

(note that c² is the greatest value)

The question is not clear, but assuming that the three areas are 25, 144 and 169, we have to replace them in the formula:

169 = 144 + 25

And the equation is satisfied. Therefore, a right triangle be formed using these squares. The sides of the triangle will be:

c = √169 = 13

b = √144 = 12

a = √25 = 5

In general terms, you need to check if the sum of the two smaller squares equals the  largest square.

tangare [24]4 years ago
6 0

Yes, the sum of the two smaller squares equals the  largest squareAnswer:

Explanation:

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Huge help needed ! im lost and need an explanation to the correct answer.
Semmy [17]

Answer:

m<MON = 100°

Explanation:

Given:

Area of shaded sector LOM = 2π cm²

NL = 6 cm

Required:

m<MON

Solution:

m<MON = 180° - m<LOM (angles in a straight line)

We don't know m<LOM. Therefore, let's find m<LOM.

Area of a sector = θ/360 × πr²

Area of sector LOM = 2π cm²

r = 3 cm

θ = m<LOM = ?

Plug in the values

2π = m<LOM/360 × π × 3²

2π = m<LOM/360 × 9π

2π = m<LOM × 9π/360

2π = m<LOM × π/40

Multiply both sides by 40

2π × 40 = m<LOM × π

80π = m<LOM × π

Divide both sides by π

80π/π = m<LOM

80 = m<LOM

m<LOM = 80°

✔️m<MON = 180° - m<LOM (angles in a straight line)

Substitute

m<MON = 180° - 80°

m<MON = 100°

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