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OleMash [197]
3 years ago
13

Which expression is equivalent to "-1 - 7"? 1 - 7 1 + 7 -1 + -7 -1 + 7

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0
-1 + -7 i pretty sure
SCORPION-xisa [38]3 years ago
4 0

Answer:

-1+-7

Step-by-step explanation:

-1 - 7= -8

1. 1 - 7=6 which is not equal to -8

2. 1+7 = 8 whihc is not equal to -8

3. -1+-7 = -1-7 = -8

4. -1+7 = 6 whihc is not equal to -8

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2. True or False: According to financial experts, a renter should allow no more than 30%
Aneli [31]

Answer:

true hope it helps?

Step-by-step explanation:

6 0
3 years ago
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Choose the correct solution and graph inequality q + 1/3 > 1/2​
kherson [118]

Answer:

first choice

Step-by-step explanation:

make 1/3 and 1/2 a common denominator, which is 6.

1x2

-      = 2

         -

3x 2   6

1 x 3  

-       =    3

             -

2 x 3      6

now u have 2/6, and 3/6

u subtract 2/6 by 3/6 since ur finding a solution to an inequality. remember to do the opposite sign.

2/6-2/6 = 0 (u cancel that out)

3/6 - 2/6 = 1/6

now u have

q>1/6

since there's no 1/6 the first choice is the most accurate

7 0
3 years ago
2x + 7 &gt; 20<br> x is an integer.<br> Find the smallest value of x.
prisoha [69]

Answer:

Step-by-step explanation:

2x + 7 > 20

2x > 13

x > 6.5

4 0
3 years ago
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How long does it take for a car to travel 250 feet at 35 mph?
DedPeter [7]
A little over 7 hours
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6) If sec theta+tan theta = P. PT sin theta=P^2-1/P^2+1 ...?
jarptica [38.1K]
I will use the letter x instead of theta.

Then the problem is, given sec(x) + tan(x) = P, show that

sin(x) = [P^2 - 1] / [P^2 + 1]

I am going to take a non regular path.

First, develop a little the left side of the first equation:

sec(x) + tan(x) = 1 / cos(x) +  sin(x) / cos(x) = [1 + sin(x)] / cos(x)

and that is equal to P.

Second, develop the rigth side of the second equation:

[p^2 - 1] / [p^2 + 1] =

= [ { [1 + sin(x)] / cos(x) }^2 - 1] / [ { [1 + sin(x)] / cos(x)}^2 +1 ] =

=  { [1 + sin(x)]^2 - [cos(x)]^2 } / { [1 + sin(x)]^2 + [cos(x)]^2 } =

= {1 + 2sin(x) + [sin(x)^2] - [cos(x)^2] } / {1 + 2sin(x) + [sin(x)^2] + [cos(x)^2] }

= {2sin(x) + [sin(x)]^2 + [sin(x)]^2 } / { 1 + 2 sin(x) + 1} =

= {2sin(x) + 2 [sin(x)]^2 } / {2 + 2sin(x)} = {2sin(x) ( 1 + sin(x)} / {2(1+sin(x)} =

= sin(x)

Then, working with the first equation, we have proved that [p^2 - 1] / [p^2 + 1] = sin(x), the second equation.


4 0
4 years ago
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