Answer:
true hope it helps?
Step-by-step explanation:
Answer:
first choice
Step-by-step explanation:
make 1/3 and 1/2 a common denominator, which is 6.
1x2
- = 2
-
3x 2 6
1 x 3
- = 3
-
2 x 3 6
now u have 2/6, and 3/6
u subtract 2/6 by 3/6 since ur finding a solution to an inequality. remember to do the opposite sign.
2/6-2/6 = 0 (u cancel that out)
3/6 - 2/6 = 1/6
now u have
q>1/6
since there's no 1/6 the first choice is the most accurate
Answer:
Step-by-step explanation:
2x + 7 > 20
2x > 13
x > 6.5
I will use the letter x instead of theta.
Then the problem is, given sec(x) + tan(x) = P, show that
sin(x) = [P^2 - 1] / [P^2 + 1]
I am going to take a non regular path.
First, develop a little the left side of the first equation:
sec(x) + tan(x) = 1 / cos(x) + sin(x) / cos(x) = [1 + sin(x)] / cos(x)
and that is equal to P.
Second, develop the rigth side of the second equation:
[p^2 - 1] / [p^2 + 1] =
= [ { [1 + sin(x)] / cos(x) }^2 - 1] / [ { [1 + sin(x)] / cos(x)}^2 +1 ] =
= { [1 + sin(x)]^2 - [cos(x)]^2 } / { [1 + sin(x)]^2 + [cos(x)]^2 } =
= {1 + 2sin(x) + [sin(x)^2] - [cos(x)^2] } / {1 + 2sin(x) + [sin(x)^2] + [cos(x)^2] }
= {2sin(x) + [sin(x)]^2 + [sin(x)]^2 } / { 1 + 2 sin(x) + 1} =
= {2sin(x) + 2 [sin(x)]^2 } / {2 + 2sin(x)} = {2sin(x) ( 1 + sin(x)} / {2(1+sin(x)} =
= sin(x)
Then, working with the first equation, we have proved that [p^2 - 1] / [p^2 + 1] = sin(x), the second equation.
