Answer:
(s.charAt(0) != s.charAt(s.length()-1))
Explanation:
public class Palindrome
{
public static void main(String[] args) {
System.out.println(isPalindrome("car"));
System.out.println(isPalindrome("carac"));
}
public static boolean isPalindrome(String s) {
if (s.length() <= 1)
return true;
else if (s.charAt(0) != s.charAt(s.length()-1))
return false;
else
return isPalindrome(s.substring(1, s.length() - 1));
}
}
You may see the whole code above with two test scenarios.
The part that needs to be filled is the base case that if the character at position 0 is not equal to the character at the last position in the string, that means the string is not a palindrome. (If this condition meets, it checks for the second and the one before the last position, and keeps checking)
