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3 years ago

Which word completely describes the rhombus? A.equilateral B.equiangular C.regular

Mathematics

2 answers:

WARRIOR [948]3 years ago

8 0

<span>it is a equilateral because it has four congruent sides.</span>

lara [203]3 years ago

5 0

I say A. because all the sides are the same.

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TIME REMAINING

arsen [322]

Answer: (3, -1)

Step-by-step explanation:

Reflecting over y = -x maps $(x, y) \longrightarrow (-y, -x)$ .

So, $F(1,-3) \longrightarrow F'(3, -1)$

5 0

1 year ago

X + x + x = 54<br> What’s the answer for this

Oliga [24]

Answer:

x = 18

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+x+x=54

(x+x+x)=54(Combine Like Terms)

3x=54

Step 2: Divide both sides by 3.

3x 3 = 54

3 x=18

Answer:

x=18

8 0

3 years ago

Read 2 more answers

Shen needs to memorize words on a vocabulary list for german class. he has memorized 12 of the words, which is two-thirds of the

katrin [286]

2/3 of the list = 12

2/3x = 12
x = 12 / (2/3)
x = 12 * 3/2
x = 36/2
x = 18 <=== there are 18 words on the list

3 0

3 years ago

Mia removes the plug from a trough to drain the water. The volume, in gallons, in the trough after it has been unplugged can be

STALIN [3.7K]

Answer:

The correct option is D) (5x − 2)(2x − 3).

Step-by-step explanation:

Consider the provided expression.

$10x^2-19x+6$

Where x is time in minutes.

We need to find the appropriate form of the expression that would reveal the time in minutes when the trough is empty.

When the trough is empty the whole expression becomes equal to 0.

Substitute the whole expression equal to 0 and solve for x that will gives us the required expression.

$10x^2-19x+6=0$

$10x^2-15x-4x+6=0$

$5x(2x-3)-2(2x-3)=0$

$(5x-2)(2x-3)=0$

Now consider the provided option.

By comparison the required expression is D) (5x − 2)(2x − 3).

Hence, the correct option is D) (5x − 2)(2x − 3).

3 0

4 years ago

Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and

Monica [59]

Step-by-step explanation:

We have got the lines :

$y=ax+b\\y=cx+d$

Both lines intercept the x-axis in the point :

$I = (i_{1} ,i_{2})$

In all point from x-axis the y-component is equal to 0.

$I=(i_{1},o)$

We replace the I point in the lines equations:

$0=a(i_{1})+b \\0=c(i_{1})+d$

From the first equation :

$0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}$

From the second equation :

$0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}$

Then $i_{1}=i_{1}$

Finally :

$\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc$

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0

3 years ago