Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

Putting all the values,
.....(1)
For maximum height, put

Put t = 1.875 in equation (1)

So, the maximum height reached by the ball is 61.25 m.
I think its 55 meters but ry to check first
Answer:

Step-by-step explanation:
Scale Factor = 5
Also,
B'C' = 24 feet
Since both are squares so both have all sides equal.
Sqaure A'B'C'D' is dilated by a scale factor of 5
So,
AB = BC = CD = DA = 24/5 = 4.8 ft.
Since absolute value is just taking the positive value of whatever you put in the function, it is 7.8 as well. Also, absolute value can be described as the distance from 0 on the number line. 7.8 is 7.8 "units" away from 0, thus meaning it is equal to 7.8.