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aliina [53]
3 years ago
10

four men and four women line up at a checkout counter in a store. In how many different ways can they line up if the first perso

n in line is a man, and the people in line alternate man, woman, man, woman, and so on?
Mathematics
2 answers:
Anika [276]3 years ago
8 0
To answer the question, make use of the Fundamental Principles of Counting. For the first person in the line, we can choose from 4 men, for the second person from 4 women. Alternately, the counting becomes,
                     4 x 4 x 3 x 3 x 2 x 2 x 1 x 1      or     4! x 4!
The answer to problem is 576.
coldgirl [10]3 years ago
5 0
The fundamental principle of counting is important to solve this particular problem. For the first person, we are able to choose from 4 men, for the second in line, we can choose from 4 women. When alternate, the counting becomes,

4 x 4 x 3 x 3 x 2 x 2 x 1 x 1

or it can be simplified to

4! x 4!

<span>Therefore, the answer is 576.</span>
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The ratio of hydrogen to oxygen atoms in water molecules is 2 to 1. If the beaker of water contained 4.1 moles of oxygen atoms,
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Answer:

8.2

Step-by-step explanation:    

We have been given that the ratio of hydrogen to oxygen atoms in water molecules is 2 to 1.      

We can represent this information as: \frac{\text{Hydrogen}}{\text{Oxygen}} =\frac{2}{1}

Let x be amount of moles of hydrogen atoms in water beaker. The proportion of hydrogen and oxygen moles will be same in water beaker.

Upon substituting our values in above proportion we will get,

\frac{2}{1} =\frac{x}{4.1}            

x=2\times 4.1              

x=8.2    

Therefore, the moles of hydrogen atoms in water beaker will be 8.2.

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