Question (1):

Price last week = $6.00
Price this week = $7.20

Increased = $7.20 - $6.00 = $1.20

Answer : Percentage increased = $1.20/$6.00 x 100 = 20%

Question (2):

Original Price = $90

Marked down = 35% of $90 = 0.35 x 90 = $31.50

Price after marked down = $90 - $31.50 = $58.50

Answer: Lilly will pay $58.50 for the football cleats.

6 0

3 years ago

Read 2 more answers

What two step equation when solved does x=-3

Travka [436]

Answer:

x + 3 = 0.

Step-by-step explanation:

One would be:

x + 3 = 0 Subtract 3 from both sides:

x + 3 - 3 = 0 - 3

x = -3

7 0

3 years ago

AB=25 , BD=4, Solve for the radius? Please help!!!!!

Alex787 [66]

9514 1404 393

Answer:

r = 14.5

Step-by-step explanation:

AD is the perpendicular bisector of chord EC, so is the diameter of the circle. The radius is half the diameter.

r = AD/2 = (AB +BD)/2 = (25 +4)/2 = 29/2

r = 14.5

Segments BE and BC are 10 = √(25·4)

4 0

3 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

3 years ago