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artcher [175]
3 years ago
12

15 points Help asap thanks so much

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0
The answer is inconsistent
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PLEASE HELP. what is the area and perimeter, show work please.
Agata [3.3K]
The area is 682.
 the perimeter is 80

4 0
4 years ago
Read 2 more answers
a rectangular box with two sqaure opposite ends is to hold 8000 cubic inches. find the dimensions of the cheapest box if tge rec
AveGali [126]

Answer:

the dimensions of the box that minimizes the cost are 5 in x 40 in x 40 in

Step-by-step explanation:

since the box has a volume V

V= x*y*z = b=8000 in³

since y=z (square face)

V= x*y² = b=8000 in³

and the cost function is

cost = cost of the square faces *  area of square faces + cost of top and bottom * top and bottom areas + cost of the rectangular sides * area of the rectangular sides

C = a* 2*y² +  a* 2*x*y + 15*a* 2*x*y =  2*a* y² +  32*a*x*y

to find the optimum we can use Lagrange multipliers , then we have 3  simultaneous equations:

x*y*z = b

Cx - λ*Vx = 0 → 32*a*y -  λ*y² = 0 → y*( 32*a-λ*y) = 0 → y=32*a/λ

Cy - λ*Vy = 0  → (4*a*y + 32*a*x) - λ*2*x*y = 0

4*a*32/λ  + 32*a*x - λ*2*x*32*a/λ = 0

128*a² /λ +  32*a*x - 64*a*x = 0

32*a*x = 128*a² /λ

x  = 4*a/λ

x*y² = b

4*a/λ * (32*a/λ)² = b

(a/λ)³ *4096 =  8000 m³

(a/λ) = ∛ ( 8000 m³/4096 ) = 5/4 in

then

x  = 4*a/λ = 4*5/4 in = 5 in

y=32*a/λ = 32*5/4 in = 40 in

then the box has dimensions 5 in x 40 in x 40 in

3 0
4 years ago
Benji, a 12 kg Border terrier, requires daily injections of ampicillin 15% for 3 days. The dose rate is 7.5
pogonyaev
<h2>Hello!</h2>

The answer is:

Benji requires 90mL per injection.

<h2>Why?</h2>

From the statement we know that dog's weight is 12 kg, and daily injections are required for 3 days, the dose rate is 7.5 mg/kg, so we need to calculate how many mL per injection does Benji require.

We have that:

Weight=12Kg\\\\Dose=7.5\frac{mL}{Kg}

If the dose rate is 7.5 mL per each Kg, how many mL are required for 12 Kg? We can set it up using the following relation:

7.5mL=1Kg\\x=12Kg\\\\x=\frac{7.5mL*12Kg}{1Kg}=\frac{90mL.Kg}{1Kg}=90mL

Hence, we have that there are needed 90 mL per injection.

Have a nice day!

6 0
3 years ago
For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8.
Lena [83]

Answer:

Option b. 0.496

Step-by-step explanation:

we know that

f(x)=0.01(2^{x})

The average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

where

a=3

b=8

f(a)=f(3)=0.01(2^{3})=0.08  

f(b)=f(8)=0.01(2^{8})=2.56

Substitute

\frac{2.56-0.08}{8-3}

\frac{2.48}{5}

0.496

3 0
3 years ago
Read 2 more answers
Someone please help me this is the last question on my homework. I have to write a quadratic equation for this word problem...
Nataly_w [17]

Answer:

57xsquare-42x=5.5

Step-by-step explanation:

8 0
4 years ago
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