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irga5000 [103]
3 years ago
12

How to pass level 4 in st math 5th grade challenge

Mathematics
2 answers:
ella [17]3 years ago
4 0
Keep practicing. Never give up. Try harder. Do it until you get it right.
Pavlova-9 [17]3 years ago
3 0

Answer:don’t give up and keeping trying until you get it

Step-by-step explanation:

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Draw graph x + y = 7 and x - y = 2 on the same graph
borishaifa [10]

Graphed in attached file and drawn!

8 0
3 years ago
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Which ordered pair represents the plotted point on the graph?
mezya [45]
Hope this helps but the answer is A.(-5,2)
7 0
2 years ago
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Evaluate (mn)(x) for x = - 3.<br> (mn)(-3) =
liubo4ka [24]

Answer:

-3mn

Step-by-step explanation:

It seems you might be missing some of the question, as you haven't given what m and n are equal to.

If the question has just given you x, then you would simply just simplify it to get -3mn.

6 0
3 years ago
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Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs
Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

AB

AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}

AB \approx 7.616

BC

BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}

BC \approx 6.325

AC

AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}

AC \approx 5.831

Now we determine the area of the triangle by Heron's formula:

A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)} (1)

s = \frac{AB+BC + AC}{2} (2)

Where:

A - Area of the triangle.

s - Semiparameter.

If we know that AB \approx 7.616, BC \approx 6.325 and AC \approx 5.831, then the area of the triangle is:

s \approx 9.886

A = 18

The area of the triangle is 18 square units.

7 0
2 years ago
How do you find an inequality on a graph ?
Helga [31]
There are three steps:<span>Rearrange the equation so "y" is on the left and everything else on the right.Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)<span>Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).</span></span>
3 0
3 years ago
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