Answer:
n ≥ -4
Step-by-step explanation:
-3/4n ≤ 3
-4/3(-3/4n) ≤ 3(-4/3)
n ≥ -12/3
n ≥ -4
CHECK:
correct
-3/4(-4) ≤ 3
12/4 ≤ 3
3 = 3
correct
-3/4(5) ≤ 3
-15/4 ≤ 3
-3.75 < 3
incorrect
-3/4(1) ≤ 3
-3/4 is not ≤ 3
3 ln 3 + 4 ln b => ln 3^3 + ln b^4 => ln (3^3)*(b^4)
which tells you that the only critical point of
occurs at (2, 1), which does lie within the region
. At this point, we get
.
Next we check along the boundaries of
. They are the lines
with
,
with
, and
with
.
If
, then
, which is monotonically decreasing and must therefore attain its maximum at
and minimum at
. We get
and
.
If
, then
, which is also monotonically decreasing and attains its maximum at
and minimum at
. We get
and
.
If
, then
. We have
, which suggests an extremum occurs at (3, 2). We get
.
So
has a minimum value of 4 at (1, 4) and (5, 0), and a maximum value of 8 at (1, 0) and (3, 2).
#1 is D. 3.875
#2 is B. 0.35
