For first 50 miles:- x + 9 = 50 / t where x is average speed for the last 68 miles and t = time taken for the first 50 miles.
For the second 68 miles:- x = 68 / (3 - t)
Substitute for x in first equation:- 68 / (3 - t) + 9 = 50/t 68t + 9t(3 - t) = 50(3 - t) 68t + 27t - 9t^2 = 150 - 50t 9t^2 - 145t + 150 = 0 t = 1.111 , 15 (ignore the 15 hours as total time = 3). so the speed for the first 50 miles = 50 / 1.111 = 45 miles per hour Answer
assuming both hyperbolas at centered at the origin, the values for the numerator and denominator will switch, so that the slope of one is the reciprocal of the other's slope.