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3 years ago

Which algebraic expression is equivalent to the expression below?

Mathematics

2 answers:

pogonyaev3 years ago

7 0

 So the right answer is of option D .

Look at the attached picture

Hope it will help you....

<h2>Follow me for more.</h2>

-pragya~~~

77julia77 [94]3 years ago

3 0

6(3x + 4) + 5(12-x) simplifies to

D) 13x + 84

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A box of 8 marbles has 4 red, 2 green, and 2 blue marbles. If you select one marble, what is the probability that it is a red or

Yakvenalex [24]

Answer:

3/4

Step-by-step explanation:

add the no. of red marbles and blue marbles

2+4 = 6

Probability so divide 6/8 simplified to 3/4

4 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$

Volume of the box at x= 1.59:

$V = \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\$

Volume of the box at x= 0.53:

$V = \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3$

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0

3 years ago

If anyone could help out with this one i would really appreciate it f(2)=?

algol13

Answer:

f(2) = 0

Step-by-step explanation:

Function f(t) is defined in three different ways depending on the value of t.

For t = 8, function f(t) is -64/t.

For t = 10, function f(t) is 14 - t.

We are not asked about f(8) or f(10). We are asked about f(2). The third definition of function f(t) is for all values of t that are not 8 or 10. 2 is not 8 or 10, so use the third definition of function f(t) and plug in 2 for t.

f(t) = t^2 - 3t + 2 for t not equal to 8 or 10.

f(2) = 2^2 - 3(2) + 2

f(2) = 4 - 6 + 2

f(2) = 0

6 0

3 years ago

How do I solve this equation? Please, if you will, explain.

Licemer1 [7]

Yes, but your answer will be a decimal, but make sure you check your work and one way you can check your work is by first combing like terms, and then solve it as it is an equation.

7 0

3 years ago

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zlopas [31]

I believe the answer is feet

4 0

4 years ago

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