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Reil [10]
3 years ago
5

What is the simplified form of the quantity of x plus 3, all over 3 + the quantity of x plus 6, all over 3?

Mathematics
1 answer:
elixir [45]3 years ago
7 0

Answer:

(2x + 9) / 3

Step-by-step explanation:

(x + 3) / 3  +   (x + 6) / 3

The denominators are both 3 so we can add the fractions as follows:-

= (x + 3) + (x + 6) / 3

= (2x + 9) / 3


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Given f(x) =
sergejj [24]

Answer:

A

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = \left\{        \begin{array}{ll}            2\cos(\pi x) \text{ for }  x \leq -1 \\ \\          \displaystyle   \frac{2}{\cos(\pi x)}\text{ for } x > -1        \end{array}    \right.

And we want to find:

\displaystyle \lim_{x\to -1}f(x)

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

\displaystyle \lim_{x\to-1^-}f(x)

Since we are approaching from the left, we will use the first equation:

\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)

By direct substitution:

=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2

Right-Hand Limit:

\displaystyle \lim_{x\to -1^+}f(x)

Since we are approaching from the right, we will use the second equation:

=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}

Direct substitution:

\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2

So, we can see that:

\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

\displaystyle \lim_{x \to -1}f(x)=-2

Our answer is A.

8 0
3 years ago
We’re almost done people!✨✨✨ also don’t make fun of what I listen to please ;-;
inessss [21]

Answer:

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Step-by-step explanation:

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pashok25 [27]
The answer is:
J = 250 17/30
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max bought an iPad for $480. when he sold it, he made a loss of 30%. How much did Max sell the iPad for?
Shalnov [3]
He sold it for $266. because 30% of 480 is 114. 480-114=266
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The first shift of GME Corporation produced 2 1/5 times as many lanterns as the second shift. GME produced 6,240 lanterns in Nov
madreJ [45]

Answer:

First shift produced 4,290 lanterns and second shift produced 1,950 lanterns.

Step-by-step explanation:

Look at the attachment

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