The time for the collision is 3.6S.
<h3>
What is collision
?</h3>
The collision is an encounter between particles resulting in exchange or transformation of energy.
According to the question,
Force,
F = 5 N
Mass,
m = 3 kg
Velocity,
v₁ = 9 m/s and v₂ = 3 m/s
As we know,
F=m*(v/t)
so,
5=3*(9-3/t)
T=3*6/5
T=18/5
hence, the time for the collision is
T= 3.6S.
Learn more about collision here,
brainly.com/question/13138178
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A figure of speech is a figure of speech in which a word or phrase is applied to an object or action to which it is not literally applicable. An example of a metaphor would be "Rollercoaster of emotions" which means, that they are experiencing a lot of good and bad things
Answer: C An unfulfilled pledge by a political leader
Explanation:
The author refers to President Obama´s promise to provide deportation assistance for families, which he hasn´t fulfilled.
As the author recalls her parents being deported by immigration officers without any regard for the union of the family or her safety as a young teenager, she highlights the President´s responsibility for bringing a solution to a problem that has had families greaving over lost family members for too long.
Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with
.
In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:
![\mu = np = 200(0.22) = 44](https://tex.z-dn.net/?f=%5Cmu%20%3D%20np%20%3D%20200%280.22%29%20%3D%2044)
![\sigma = \sqrt{np(1 - p)} = \sqrt{200(0.22)(0.78)} = 5.8583](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7Bnp%281%20-%20p%29%7D%20%3D%20%5Csqrt%7B200%280.22%29%280.78%29%7D%20%3D%205.8583)
The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{30.5 - 44}{5.8583}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B30.5%20-%2044%7D%7B5.8583%7D)
Z = -2.3
Z = -2.3 has a p-value of 0.0107.
0.0107 = 1.07% probability that more than 30 are single.
More can be learned about the normal distribution at brainly.com/question/24663213
Try taking a mesure instrument of any kind (like a ruler or measuring tape) and put it along your arm.