Question

Help need on 2 algebra problems !!!!!!! please

Answer 1

Answer:

1) C. 2

2) A. 2

Step-by-step explanation:

1. We need to descompose 256 into its prime factors:

$256=2*2*2*2*2*2*2*2=2^8$

We must rewrite the expression $\sqrt[8]{256}$:

$=\sqrt[8]{2^8}$

We need to remember that:

$\sqrt[n]{a^n}=a$

Then:

$=2$

2. Let's descompose 16 into its prime factors:

$16=2*2*2*2=2^4$

We must rewrite the expression $\sqrt[4]{16}$:

$=\sqrt[4]{2^4}$

Then we get:

$=2$