With what?????I don’t see anything only ur text
Answer:
Perpendicular
Step-by-step explanation:
The two equations intersect at a right angle, so they are perpendicular.
Answer:

Step-by-step explanation:
<u>Given information</u>:
- Polynomial function with real coefficients.
- Zeros: 0, 2i and (3+i).
For any complex number
, the complex conjugate of the number is defined as
.
If f(z) is a polynomial with real coefficients, and z₁ is a root of f(z)=0, then its complex conjugate z₁* is also a root of f(z)=0.
Therefore, if f(x) is a polynomial with real coefficients, and 2i is a root of f(x)=0, then its complex conjugate -2i is also a root of f(x)=0.
Similarly, if (3+i) is a root of f(x)=0, then its complex conjugate (3-i) is also a root of f(x)=0.
Therefore, the polynomial in factored form is:


As we have not been given a leading coefficient, assume a = 1:

Expand the polynomial:







Answer:
c
Step-by-step explanation:
First, from A to B, x=6, but y ranges from 8 to -8. From B to C, y=-8, but x ranges from 6 to -6. From C to D, x=-6, but y ranges from -8 to 8. From D to A, y=8, but x ranges from -6 to 6.
The ranges are as follows:
- x goes from -6 to 6
- y goes from -8 to 8
There are no x values less than -6, no x values greater than 6, no y values less than -8, and no y values greater than 8. x is always greater than or equal to -6 and less than or equal to 6. y is always greater than or equal to -8 and less than or equal to 8. We can write these as inequalities as follows:
x ≥ -6
x ≤ 6
y ≥ -8
y ≤ 8
The answer that is not in these 4 is c. y ≤ -8. y is never less than -8, so this is wrong