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Solnce55 [7]
3 years ago
6

At time t = 0 you have 100 grams of radioactive Chromium-48. Ten hours later you have 74 grams left. What is the half life of Ch

romium-48?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
6 0
To calculate what is asked we use the formula for radioactive decay. It is expressed as follows:

An = Ao (e^(-kt))

We calculate as follows:

An = Ao (e^(-kt))
74 = 100 (e^(-k(10)))
k = 0.0301

1/2 = (e^(-0.0301t))
t = 23 hours

Hope this answers the question.
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Step-by-step explanation:

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PLEASE HELP ME!!!!! (Urgent)
defon

Answer:

f(x)=x^5-6x^4+14x^3-24x^2+40x

Step-by-step explanation:

<u>Given information</u>:

  • Polynomial function with real coefficients.
  • Zeros: 0, 2i and (3+i).

For any complex number   z=a+bi , the complex conjugate of the number is defined as  z^*=a-bi.  

If f(z) is a polynomial with real coefficients, and z₁ is a root of f(z)=0, then its complex conjugate z₁* is also a root of f(z)=0.

Therefore, if f(x) is a polynomial with real coefficients, and 2i is a root of f(x)=0, then its complex conjugate -2i is also a root of f(x)=0.

Similarly, if (3+i) is a root of f(x)=0, then its complex conjugate (3-i) is also a root of f(x)=0.

Therefore, the polynomial in factored form is:

f(x)=ax(x-2i)(x-(-2i))(x-(3+i))(x-(3-i))

f(x)=ax(x-2i)(x+2i)(x-3-i)(x-3+i)

As we have not been given a leading coefficient, assume a = 1:

f(x)=x(x-2i)(x+2i)(x-3-i)(x-3+i)

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f(x)=x(x^2+2ix-2ix-4i^2)(x^2-3x+xi-3x+9-3i-xi+3i-i^2)

f(x)=x(x^2-4i^2)(x^2-6x+9-i^2)

f(x)=x(x^2-4(-1))(x^2-6x+9-(-1))

f(x)=x(x^2+4)(x^2-6x+10)

f(x)=(x^3+4x)(x^2-6x+10)

f(x)=x^5-6x^4+10x^3+4x^3-24x^2+40x

f(x)=x^5-6x^4+14x^3-24x^2+40x

8 0
2 years ago
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Alexeev081 [22]

Answer:

c

Step-by-step explanation:

First, from A to B, x=6, but y ranges from 8 to -8. From B to C, y=-8, but x ranges from 6 to -6. From C to D, x=-6, but y ranges from -8 to 8. From D to A, y=8, but x ranges from -6 to 6.

The ranges are as follows:

- x goes from -6 to 6

- y goes from -8 to 8

There are no x values less than -6, no x values greater than 6, no y values less than -8, and no y values greater than 8. x is always greater than or equal to -6 and less than or equal to 6. y is always greater than or equal to -8 and less than or equal to 8. We can write these as inequalities as follows:

x ≥ -6

x ≤ 6

y ≥ -8

y ≤ 8

The answer that is not in these 4 is c. y ≤ -8. y is never less than -8, so this is wrong

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