Question

2. An urn contains two red, three white and five blue balls. A player draws one ball from the urn. If the ball is red the player receives $5. If the ball is white, the player pays $8. If the ball is blue, the player receives $2. Find the expected value of a draw.

Answer 1

Answer:

The player will recieve $2.

Step-by-step explanation:

Since we are not told what color ball you chose at random, and instead are asked to find the expected value. Then the expected ball color would be the ball with the highest probability of getting chosen.

Therefore, we need to find the probability of each color ball inside the bag. According to the question there are,

2 red + 3 white + 5 blue = 10 total balls

So the probabilities would be the following,

1. Red: $\frac{2}{10}$
2. White: $\frac{3}{10}$
3. Blue: $\frac{5}{10}$

So we can see that the ball with the highest probability of getting picked is the blue ball. Since the Blue ball has a value of $2, then the player will recieve $2.

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