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dimaraw [331]
3 years ago
9

Which of the following transforms the graph of y=x^2 to the graph of y=x^2-7?

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0

You're performing this kind of transformation:

f(x)\mapsto f(x)+k

This kind of transformations translate the functions vertically k units up if k is positive, k units down if k is negative.

So, in your case, you translate the function 7 units down.

Thepotemich [5.8K]3 years ago
4 0

Answer:

1.) a translation 7 units to the right

2.) a translation 7 units to the left

3.) translation 7 units down

4.) a translation 7 units up                

Step-by-step explanation:

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The complete question in the attached figure

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2/9 times n = -6. find the value of n. Please help!
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5 0
3 years ago
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How do you solve this?
lutik1710 [3]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^?}{8^3}=\cfrac{1}{8^8}\implies \cfrac{8^?}{8^3}=8^{-8}\implies 8^?=8^3\cdot 8^{-8}\implies 8^?=8^{3-8}\implies 8^?=8^{-5}


\bf \begin{array}{llll} \textit{if the bases are the same, for}\\ \textit{the equation to be true, the}\\ \textit{exponents must also be the same} \end{array}~\hspace{5em}?=-5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{1}{r^3}=r^{-7}\cdot r^?\implies r^{-3}=r^{-7+?}\implies \stackrel{\textit{bases are the same, so are the exponents}}{-3=-7+?\implies 4=?}

7 0
3 years ago
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