I need help with number 3

Mathematics

1 answer:

masha68 [24]4 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Anna-Maria has added 4 quarts of an alcohol in water solution to 1 quart of water and her ending product is a 36% alcohol in wat

fomenos

The concentration of solution would be the amount of the molecule divided by the volume. In this case, the solution concentration is 36% and the volume is 4 quarts + 1 quarts= 5 quarts. You are asked the concentration before 1 quarts added. The alcohol content should be same for both solutions. The answer should be:

concentration = alcohol content/ volume
alcohol content =concentration * volume
alcohol content1 =alcohol content2
36% * 5 quarts = concentration2 * 4quarts
concentration2= 36% * 5 quarts / 4 quarts= 45%

5 0

4 years ago

One gallon of paint covers 400 square feet of surface area. A typical spherical water tower holds 66,840.28 cubic feet of water.

enot [183]

Answer: There will enough to paint the outside of a typical spherical water tower.

Step-by-step explanation:

1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:

$V=\frac{4}{3}r^{3}\pi\\\frac{3V}{4\pi}=r^{3}\\r=\sqrt[3]{\frac{3V}{4\pi}}$

2. Substitute values:

$r=\sqrt[3]{\frac{3(66,840.28ft^{3})}{4\pi}}=25.17ft$

3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:

$SA=4r^{2}\pi\\SA=4(25.17ft)^{2} \pi\\SA=7,964.95ft^{2}$

3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.

$25*400ft^{2}=10,000ft^{2}$