To solve this problem, we make use of the Binomial
Probability equation which is mathematically expressed as:
P = [n! / r! (n – r)!] p^r * q^(n – r)
where,
n = the total number of gadgets = 4
r = number of samples = 1 and 2 (since not more than 2)
p = probability of success of getting a defective gadget
q = probability of failure = 1 – p
Calculating for p:
p = 5 / 15 = 0.33
So,
q = 1 – 0.33 = 0.67
Calculating for P when r = 1:
P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3
P (r = 1) = 0.3970
Calculating for P when r = 2:
P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2
P (r = 2) = 0.2933
Therefore the total probability of not getting more than
2 defective gadgets is:
P = 0.3970 + 0.2933
P = 0.6903
Hence there is a 0.6903 chance or 69.03% probability of
not getting more than 2 defective gadgets.
Answer:
There are 60 monkeys in the Zoo
Step-by-step explanation:
In this question, we are asked to calculate the number of monkeys in a Zoo given some information to use.
Let’s have the total number of monkeys be m.
60% are going monkeys. This means number of young monkeys is 0.6m.
The number of baby and old monkeys is obviously 0.4m.
Ratio of baby to old monkeys is 3:1. This means if we splitter 0.4m into 4, number of baby monkeys is 0.3m while number of old monkeys is 0.1m
Now, subtracting the number of baby monkeys from young monkeys give a total of 18 monkeys.
Let’s project this mathematically;
This means ;
0.6m - 0.3m = 18
0.3m = 18
m = 18/0.3
m = 60
There are 60 monkeys in the zoo
Answer:
5/3 or 1.66 or 1 2/3
Step-by-step explanation:
30/18 you can simply it to the factor of 6 or use a calc
5/3 if the person asks in fraction form and if they say that it can't be an improper fraction then it is 1 2/3 or get 1.6666 in calcutor
Answer:
should be xy^4/4
Step-by-step explanation:
next to the last step (x^3(y^3)^4)^1/3
