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Yuliya22 [10]
2 years ago
10

Convert the following statement using an "if-then" structure.

Mathematics
1 answer:
GaryK [48]2 years ago
6 0

Answer:

  D. If John owns a dog, then he owns a cat

Step-by-step explanation:

The implication p → q (if p, then q) has the same truth table as the logical expression ~p∨q. You have the expression ...

  ~(John owns a dog) ∨ (he owns a cat)

Matching parts of this expression to the components of the expression ~p∨q, we see we can choose ...

  • p = John owns a dog
  • q = he owns a cat

and put those into the structure of the implication: if p, then q.

  If John owns a dog, then he owns a cat. . . . . matches choice D

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V≈1.32×105cm³=31.6cm
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3 years ago
Read 2 more answers
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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3 years ago
How do you write (-4)^-5 using a positive exponent?
densk [106]

Answer:

multiply it and you can change it done ez as pie

Step-by-step explanation:

7 0
2 years ago
12. The weight of 7 chocolate bars in grams are 131, 127,125,127,133,129 and 127
Amanda [17]

Answer:

The range is from 125 to 133.

Step-by-step explanation:

That's the lowest and highest the weights go, therefore the range is from 125 and anything in between up to 133.

7 0
3 years ago
Write a quadratic equation in standard form.
Naya [18.7K]

Answer:

  1.  x^2 +2x -24 = 0

  2.  x^2 -7x +10 = 0

Step-by-step explanation:

If you look at the factored and expanded forms of a quadratic with solutions p and q, you see ...

  (x -p)(x -q) = x^2 -(p+q) +pq

The x-term coefficient is the opposite of the sum of solutions.

The constant is the product of solutions.

This knowledge lets you write down the standard form equation with no particular effort.

1.  x^2 +2x -24 = 0

2.  x^2 -7x +10 = 0

5 0
2 years ago
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