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lutik1710 [3]
3 years ago
14

Whats the solution X3=9

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

x=2.080084

Step-by-step explanation: take cube root

Yuki888 [10]3 years ago
6 0

Answer:

Forgive me if i am incorrect but i am pretty sure if i am not mistaken x=3*3=9

Step-by-step explanation:

When you look at it x is attach to the 3 thus making it multiplication  but you would have to do the opposite. Which is division so 9 divide by 3 is 3.

Hope this help you

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Answer:

b hopefully this helps you with work

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3 years ago
Emma tossed a six-sided die two times and recorded the sum of the two numbers. How many different sums are possible for her to r
guajiro [1.7K]

Answer:

11

Step-by-step explanation:

6 times 6 is 36

Think about this you row a 1 first the possible result of the next row is 1,2,3,4,5,or 6 and that is 6 possible sums.

Which is 2, 3, 4, 5, 6, and 7

Next she rows 2 with again 6 possible results

Which is 3, 4, 5, 6, 7,and 8

Then she rows a 3, 4, 5,and 6

with the possible results

4, 5, 6, 7, 8, 9

   5, 6, 7, 8, 9, 10

       6, 7, 8, 9, 10, 11

           7, 8, 9, 10, 11, 12

They asked for different sums so out of the results the different sums is

2, 3, 4, 5, 6, 7, 8, 9, 10, 11,and 12

HOPE THIS HELPS:)

5 0
3 years ago
12. What is the area of the quadrilateral?
ivolga24 [154]
The answer is A 100 square centimeters
4 0
2 years ago
Ms.wolf has 9.5 pounds of candy in her classroom. she gives each student 0.25 pounds of candy. how many students can she feed​
LekaFEV [45]

Answer:

9.5÷0.25=38

So she can feed 38 students.

5 0
2 years ago
A car insurance company has determined that 9% of all drivers were involved in a car accident last year. among 14 drivers living
andriy [413]

The probability of getting 3 or more who were involved in a car accident last year is 0.126.

Given 9% of the drivers were involved in a car accident last year.

We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.

We have to use binomial theorem which is as under:

nC_{r}p^{r} (1-p)^{n-r}

where p is the probability an r is the number of trials.

Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]

=1-{14C_{0}0.9^{0} (0.1)^{14} +14C_{1} (0.9)^{1} (0.1)^{13} +14C_{2} (0.9)^{2} (0.1)^{12}}

=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}

=1-{0.2670+0.3654+0.2358}

=1-0.8682

=0.1318

Among the options given the nearest is 0.126.

Hence the probability that 3 or more are involved in the accident is 0.126.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0
1 year ago
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