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skad [1K]
3 years ago
7

Solve for t if p≠q (t+p)/q - q/p = (t-q)/p + p/q

Mathematics
1 answer:
german3 years ago
6 0

Answer:

.. q T 0 = (q/p)a (q/p)a − (q/p)T−10 if p ≠ q and qT0 = 1 − T0/a if p = q = 1/2.

Step-by-step explanation:

Suppose that there are two different solutions, p and q, in [a, b]. Thus p =g(p) q =g(q) p ≠ q The function g(x) satisfies the hypotheses of the mean-value ... that g(p) –g(q) = (p – q) g׳(t) Because g(p) =p and g(q) = q, the left side of Eq. (1-3) may...

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meriva
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3 years ago
Emma has 4 1/2 pounds of birdseed. She wants to divide it evenly among 3 bird feeders. How much birdseed should she put in each?
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7 0
2 years ago
NO LINKS!!!!!
8090 [49]

9514 1404 393

Answer:

  5x^2 +10x = -5

Step-by-step explanation:

The equation will have one solution when the discriminant is zero.

In standard form, the equation is ...

  ax^2 +10x -c = 0

The discriminant of the equation ax^2+bx+c=0 is  ...

  b^2 -4ac

so the discriminant of your equation is ...

  10^2 -4a(-c) = 100 +4ac

We want that to be zero, so we require ...

  100 +4ac = 0

  25 +ac = 0

  ac = -25

Any pair of values of 'a' and 'c' that have a product of -25 will satisfy the requirement. As you state, one possible pair is a = 5 and c = -5. Putting these values into the given equation makes it ...

  5x^2 +10x = -5 . . . . . the equation with a=5, c=-5

_____

<em>Additional comment</em>

Your problem statement does not require that 'a' be non-zero. If <em>a=0</em>, then the equation will have one real solution for <em>any value of c</em>.

If you restrict the solutions to integers, then possibilities include ...

  (a, c) = (1, -25), (5, -5), (25, -1), (-25, 1), (-5, 5), (-1, 25)

6 0
2 years ago
How do i convert 37/4 into mixed numbers
IrinaVladis [17]
How many times does (4) go into (37) ?  9 TIMES.

Remainder 1.

So as a mixed number would be 9 whole number, 1/4

= (9 1/4)
4 0
3 years ago
Please help. Here's the question
kakasveta [241]
He goes 1.5k/h. To get that you divide the km by the hour. Then multiply the hour by 1.5 to get the km. (Ex. 2hrs x 1.5km = 3km)
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