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skad [1K]
3 years ago
7

Solve for t if p≠q (t+p)/q - q/p = (t-q)/p + p/q

Mathematics
1 answer:
german3 years ago
6 0

Answer:

.. q T 0 = (q/p)a (q/p)a − (q/p)T−10 if p ≠ q and qT0 = 1 − T0/a if p = q = 1/2.

Step-by-step explanation:

Suppose that there are two different solutions, p and q, in [a, b]. Thus p =g(p) q =g(q) p ≠ q The function g(x) satisfies the hypotheses of the mean-value ... that g(p) –g(q) = (p – q) g׳(t) Because g(p) =p and g(q) = q, the left side of Eq. (1-3) may...

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62 = 9z + 17<br> Solve for Z
Lina20 [59]

Answer : Z = 5

Step-by-step explanation :

62 = 9z + 17

-17 -17

45 = 9z

/9 /9

5 = z

Plug it back in :

62 = 9(5) + 17

62 = 45 + 17

62 = 62

7 0
3 years ago
How do you write 18/40 in a decimal
In-s [12.5K]

Answer:

0.45 you divide them

4 0
3 years ago
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Please help! Thank you! I'm crying in confusion!
djyliett [7]
4*-13=-52
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3 years ago
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The map shows the route for a race.You are at X, 6000 ft from the first checkpoint C.The second checkpoint D is located at the m
Alex

Answer:

Distance between the two check point (C and D) is 4920 ft.

Step-by-step explanation:

From the question given above, we obtained the following information:

X is 6000 ft from C (1st check point)

D (2nd check point) is the midpoint point between C and Y ( the end of the race)

Total race = 3 miles

1 mile = 5280 ft

Next, we shall express the total race in feet (ft).

This is illustrated below:

1 mile = 5280 ft

Therefore,

3 miles = 3 × 5280 = 15840 ft

Next, we shall determine the distance between the 1st check point (C) and the end of the race (Y)

This can be obtained as follow:

Total distance = 15840 ft

Distance between X and C = 6000 ft

Distance between C and Y =?

Distance between C and Y = (Total distance) – (Distance between X and C)

Distance between C and Y = 15840 – 6000

Distance between C and Y = 9840 ft

Finally, we shall determine the distance between the two check point (C and D) as follow:

Since D is midpoint between C and Y, therefore, we shall we shall divide the distance between C and Y by 2 in order to obtain the distance between the two check point (C and D).

This is illustrated below:

Distance between C and Y = 9840 ft

Distance between the two check point (C and D) = 9840/2 = 4920 ft

Therefore, the distance between the two check point (C and D) is 4920 ft

5 0
3 years ago
Write out the form of the partial fraction decomposition of the function (See Example). Do not determine the numerical values of
Vitek1552 [10]

Answer:

\frac{x^4+5}{x^3(x^2+6)} =\frac{A}{x}+\frac{B}{x^2}+\frac{D}{x^3}  +\frac{Ex+F}{x^2+6}

Step-by-step explanation:

\frac{x^4+5}{x^5+6x^3}

\frac{x^4+5}{x^3(x^2+6)} =\frac{A}{x}+\frac{B}{x^2}+\frac{D}{x^3}  +\frac{Ex+F}{x^2+6}

3 0
3 years ago
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