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Advocard [28]
4 years ago
8

10

Mathematics
1 answer:
givi [52]4 years ago
3 0

Answer: The right option that represents possible inputs and outputs of the function is the ordered pair

{(-2, -18), (2, 14), (0, -2)}

Step-by-step explanation:

By crosschecking;

Y=8x-2

When x=-2 , y= 8(-2) -2 , y= -16-2, y=-18 . (-2,-18)

When x=2 , y= 8(2) -2 , y= 16-2, y= 14

(2,14)

When x=0 , y= 8(0) -2 ,y= 0-2, y= -2

(0,-2)

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A car wheel is 56 cm in diameter. A. How far does the car go in one revolution of the wheel?
andre [41]

The car moved 175.84 cm in one revolution

The car has moved 17584 cm in 100 revolutions

<em><u>Solution:</u></em>

Given that car wheel is 56 cm in diameter

diameter = 56 cm

To find: distance traveled in one revolution of wheel

Usually wheel is of circular shape

one revolution of wheel = circumference of circle

<em><u>The circumference of circle is given as:</u></em>

c = 2 \pi r

We know that,

diameter = 2(radius)

d = 2r

<em><u>So the circumference becomes:</u></em>

c = \pi d

substitute \pi = 3.14 and d = 56 cm

c = 3.14 \times 56 = 175.84

Thus the car moved 175.84 cm in one revolution

<em><u>B. How far does it go in 100 revolutions</u></em>

Distance covered in 100 revolutions = 100 x Distance covered in 1 revolution

\rightarrow 100 \times 175.84 = 17584

Thus the car has moved 17584 cm in 100 revolutions

6 0
4 years ago
Find the area of the following triangles:
statuscvo [17]

Answer:

26) 1/2 b×h

= 1/2(8×9)

=1/2(72)

=36

27)1/2b×h

=1/2(12×15)

=1/2(180)

=90

28)a÷b×2

=(60÷8)×2

=15

29)1/2b×h

=1/2(16×1/2)

=1/2(8)

=4

30)1/2b×h

=1/2(18×12)

=1/2(216)

=108

8 0
3 years ago
На какой угол повернётся минутная стрелка за:30мин,15мин,10мин,1мин. Плиииииииииизззззззззззз и желательно быстрей
jolli1 [7]
30 mins = 180°
15 mins = 90°
10 mins = 60°
1 min = 6°

hope this helps you

5 0
3 years ago
Read 2 more answers
Hii, can you help me ?
frez [133]

Answer:

The answer is about 15 cm because if you use a ruler, it is a little under 15cm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
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