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castortr0y [4]
3 years ago
9

How many baseballs would fit into a box that has the dimensions (3*5)*2

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0

3*5= 15

15*2= 30

30 baseballs

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Please help. Flow chart proof. I'll give brainliest
AveGali [126]

Step-by-step explanation:

Statement | Reason

CB=AB         Given

DBC=DBA   Given

DB = DB      Reflexive Property

/_\ DBC

=~

/_\DBA        SAS

Sorry for the formatting the =~ means congruent.

4 0
2 years ago
Can she get some help
Artemon [7]

Answer:

-55

Step-by-step explanation:

the sqeuence seems to be subtracting by 2 everytime.

so it will be -1,-3,-5,-7,-9,-11,-13,-15,-17,-19,-21,-23,-25,-27,-29..

the answer will be 27*-2(-54) -1(because we start at -1 , not 0)

5 0
3 years ago
Read 2 more answers
Ebert used to make $22 an hour, but got a 10% raise. How much more will he make in a 40 hour work week with the raise?
Helen [10]

Answer: $88.00 per week


Step-by-step explanation: 10% of 22 is 2.2.  22 + 2.2 = 24.20 per hour

Multiply 24.20x40hours = 968.00

Multiply 22.00x40 hours =880.00

Subtract 968-880=88.00 his new weekly pay minus his old weekly pay



3 0
3 years ago
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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
Please help pic below
kvasek [131]
Πr^2=area 9=r 9^2=81π=254.47
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3 years ago
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