Create a function called "strip_r_o" that takes in a STRING and strips all the Rs and Os from the string. Also use a FOR loop in
you program to check each letter of the STRING
Python
Python
1 answer:
Answer:
The program is as follows (Take note of the comments and see attachment)
#Start of Program
def strip_r_o(word): #Declare Function strip_r_o
resultt = "" #initialize resultt to empty string
for i in range(len(word)): #Iterate from first character of input string to the last
if (not word[i] == "R") and (not word[i] == "O"): #Check if current character is not R and O
resultt = resultt + word[i] #if condition is true, add character to resultt
print(resultt) #Print string after character has been removed
#End of Function
Word = input("Enter a string: ") #Prompt user for input
strip_r_o(Word) #Call strip_r_o function
#End of Program
Explanation:
The program starts and end with a comment
Line 2 of the program declares function strip_r_o
Line 3 initializes a string variable resultt to an empty string
Line 4 iterates from first character of input string to the last
Line 5 checks each character for O or R
If true, line 6 is executed by removing O or R from the input string and saving what's left in variable resultt
Line 7 prints the end result after O and R have been removed from the input string
Line 8 is a comment
Line 9 prompts user for an input string
Line 10 calls the strip_r_o function
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Answer:
Complete Python code with step by step comments for explanation are given below.
Python Code:
# creating a function named scrabble_number that will take num as input argument
def scrabble_number(num):
# print the original number
print("The original number is: ",num)
# we can implement the required logic by using python built-in functions join() and zip()
scrambled = ''.join([char[1]+char[0] for char in zip(num[::2], num[1::2])])
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Driver code:
scrabble_number('123456')
Output:
The original number is: 123456
The scrambled number is: 214365
