Determine the width of the pond. Please explain
1 answer:
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Answer:
7) d)
standard error of the mean of one sample of 'n' observation = 0.20
8) a)
The margin of Error = 0.392
9) d
The 95% of confidence intervals are (8.61 , 9.39)
Step-by-step explanation:
7)
solution:-
The Given data sample size 'n' = 81
Given Population standard deviation 'σ' = 1.8 hours
The standard error of the mean of one sample of 'n' observation is
Standard error (SE)
=
= σ / √n
=
standard error of the mean of one sample of 'n' observation = 0.20
8)
Solution:-
The Given data sample size 'n' = 81
Given Population standard deviation 'σ' = 1.8 hours
Given the probability is 0.95
The z- score = 1.96 at 0.05 level of significance.
The margin of Error =
=
=
= 0.392
The margin of Error = 0.392
9)
Solution:-
<u>The 95% of confidence intervals are </u>
<u></u><u></u>
<u></u><u></u>
(9 - 0.392 , (9 + 0.392)
(8.609 , 9.392)
<u>The 95% of confidence intervals are </u>(8.61 , 9.39)