El horario y el minutero de un reloj miden respectivamente 0.7 y 1.2cm. Determinar la distancia entre los extremos de dichas man
ecillas a las 13:30 horas
1 answer:
Answer:
1.5887 cm
Step-by-step explanation:
If the time is 13:30, The hour pointer will be between the numbers 1 and 2.
Each number of the 12 number clock is separated by 30 degrees, so the hour pointer is at 45 degrees.
The minute pointer is at 30 minutes, so it is in number 6, being therefore at angle 180.
The angle formed by the pointers will be 180 - 45 = 135 degrees.
We can draw a triangle with both pointers and this angle (image attached)
So, we can calculate the distance between the tip of the pointers (let's call it "d") using law of cosines:
d^2 = 0.7^2 + 1.2^2 - 0.7*1.2*cos(135)
d^2 = 0.49 + 1.44 - (-0.5940) = 2.524
d = 1.5887 cm
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hello your question is incomplete attached below is the complete question
answer :
<em>Daniels sister is not correct because the time that will be taken by Daniel will be greater than the initial total time taken by Daniel.</em>
Step-by-step explanation:
<u>First determine the time it will take Daniel to reach the Boat and the jogging time</u>
time = distance / rate
where distance can be calculated using this equation: sin 53° = 400 / x
hence x ( distance ) = 500 ft
rate = 150
therefore Time ( t ) to reach boat = 500 / 150 = 3.33 minutes
Time for jogging ( as calculated ) = 3.69 minutes
therefore total time taken by Daniel = 3.33 + 3.69 = 7.02 minutes
<u>Finally determine if Daniel's sister is correct that he should have swam to the boat ramp and then jogged </u>
lets assume Distance to swim = x ( according his sister )
determine the value of x = therefore X = 1456.02 feet
∴
Total time to be taken if Daniel follows his sister's instruction = 1456.02 / 150 = 9.71 minutes
<em>Daniels sister is not correct because the time that will be taken by Daniel will be greater than the initial total time taken by Daniel.</em>
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