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IgorLugansk [536]
3 years ago
11

El horario y el minutero de un reloj miden respectivamente 0.7 y 1.2cm. Determinar la distancia entre los extremos de dichas man

ecillas a las 13:30 horas

Mathematics
1 answer:
Fed [463]3 years ago
8 0

Answer:

1.5887 cm

Step-by-step explanation:

If the time is 13:30, The hour pointer will be between the numbers 1 and 2.

Each number of the 12 number clock is separated by 30 degrees, so the hour pointer is at 45 degrees.

The minute pointer is at 30 minutes, so it is in number 6, being therefore at angle 180.

The angle formed by the pointers will be 180 - 45 = 135 degrees.

We can draw a triangle with both pointers and this angle (image attached)

So, we can calculate the distance between the tip of the pointers (let's call it "d") using law of cosines:

d^2 = 0.7^2 + 1.2^2 - 0.7*1.2*cos(135)

d^2 = 0.49 + 1.44 - (-0.5940) =  2.524

d = 1.5887 cm

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3 years ago
Help! How would I solve this trig identity?
NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}

Then the identity can be rewritten as:

sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\

Now we can multiply both sides by cos⁴(x) to get:

\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)

Now we can use the identity:

sin²(x) + cos²(x) = 1

1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

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1 year ago
what is the graph of an arithmetic sequence whose first term is 1 and whose common difference is 0.5?
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The graph will be a set of disjoint points with coordinates [n, 0.5*(1+n)]
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Explain how to determine if the triangle is an isosceles? Use algebraic formulas to SHOW
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Answer: Hope This Helps!

Step-by-step explanation:

Use the distance formula to calculate the side length of each side of the triangle. If any 2 sides have equal side lengths, then the triangle is isosceles.

More precise info: Given the coordinates of the triangle's vertices, to prove that a triangle is an isosceles plot the 3 points (optional) use the distance formula to calculate the side length of each side of the triangle. If any 2 sides have equal side lengths, then the triangle is isosceles.

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GOOD QUESTION BELOW PLS LOOK AT PHOTO
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