Question

given the digits 0-9 how many three digit arrangements are there in a lock if no number can be used twice?

Answer 1

Answer:

720 Arrangements

Step-by-step explanation:

Given the numbers could be from 0 - 9 and none of them is to be repeated.

The first place could be filled in 10 ways. (0 - 9)

The second place could be filled in 9 ways. (Excluding the one in the first place).

The third place could be filled in 8 ways. (Excluding the two numbers in the first two places).

Therefore, the total number of arrangements possible for the lock is: $10 \times 9 \times 8$ = 720 ways.