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Burka [1]
3 years ago
15

Can somebody please check my answers?

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0
I do think it's A and B. :) 
timofeeve [1]3 years ago
4 0

Answer:

Option B is right.

Step-by-step explanation:

Given that Three dentists wanted to compare the ages of their patients. They each calculated their patients’ mean age and the mean absolute deviation of their ages. They displayed the results in a table.  

Dentist      Mean      MAD

Appiah         43         9.7

Cantwell       29       13.9

Singh            41         14.1

Mean absolute deviaiton is a measure of deviations of all entries from the mean.

We find that maximum variation is that of Singh followed by Cantwell and Appaiah.

Option A is wrong as Dr. Appiah’s patients’ ages do not vary more than do Dr. Cantwell’s patients’ ages.  

B. is true.

Dr. Appiah’s patients’ ages vary less than do Dr. Singh’s patients’ ages.  

C is false  Dr. Cantwell’s patients’ ages and Dr. Singh’s patients’ ages vary about the same since tey are 13.9 and 14.1 hence different.

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Answer:

That is the simplest form.

Step-by-step explanation:

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3 years ago
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Answer:

13

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Is there a direct proportion in 3y=1/2x? if there is one, what is the constant of proportionality?
kipiarov [429]
A direct proportion is any equation where y = mx+b. (i.e., a linear equation)

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General Logs Banana Bombs cereal is sold in 10.40 ounce packages. Because the cereal is sold by weight, the number of pieces of
emmasim [6.3K]

Answer:

The 99% confidence interval for the true mean number of Banana Bombs in 10.40 ounce packages is between 689.3 and 703.86.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{12.33}{\sqrt{19}} = 7.28

The lower end of the interval is the sample mean subtracted by M. So it is 696.58 - 7.28 = 689.3 pieces

The upper end of the interval is the sample mean added to M. So it is 696.58 + 7.28 = 703.86 pieces

The 99% confidence interval for the true mean number of Banana Bombs in 10.40 ounce packages is between 689.3 and 703.86.

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