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Klio2033 [76]
3 years ago
8

Rachel has a bag that contains a total of 224 red and yellow candies. The ratio of red candies, R , to yellow candies, Y , is 3

to 4.
How many red candies are in Rachel's bag?
Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

96 red

Step-by-step explanation:

96 red, 128 yellow; 3/4=.75; r+y=224; .75y+y=224; 1.75y=224; 224/1.75=128, 224-128=96

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12+root of 35 divided by 2 + 12-2 root of 35 divided by 2
nadya68 [22]
So : 12+ \frac{\sqrt{35}}{2} + \frac{12-2 \sqrt{35} }{2}?

First, you want to bring everything together on the top of the fraction. 
12=24/2 so you can have \frac{24+ \sqrt{35}+12-2 \sqrt{35} }{2}

Add like terms -- 12 +24 = 36       \sqrt{35}-2 \sqrt{35} = \sqrt{35}

Now we are at \frac{24+ \sqrt{35} }{2} Which is the lowest possible simplified version while remaining at exact value. 

Feel free to check my math! I kinda did this off the top of my head. 
8 0
3 years ago
If g(x) = 2x + 4, find g(1).
JulijaS [17]
G(1) = 2(1) + 4 = 6
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6 0
4 years ago
196 divided by 3.5 show your work
Ilya [14]

Answer:

56

Step-by-step explanation:

Sorry for not showing my work im a mental worker

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5 0
3 years ago
Solve for x write the exact answer using either base -10 or base-e logarithms
jeka57 [31]

<u>Given</u>:

The given expression is 2^{x+5}=13^{2 x}

We need to determine the value of x using either base - 10 or base - e logarithms.

<u>Value of x:</u>

Let us determine the value of x using the base - e logarithms.

Applying the log rule that if f(x)=g(x) then \ln (f(x))=\ln (g(x))

Thus, we get;

\ln \left(2^{x+5}\right)=\ln \left(13^{2 x}\right)

Applying the log rule, \log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x), we get;

(x+5) \ln (2)=2 x \ln (13)

Expanding, we get;

x \ln (2)+5 \ln (2)=2 x \ln (13)

Subtracting both sides by 5 \ln (2), we get;

x \ln (2)=2 x \ln (13)-5 \ln (2)

Subtracting both sides by 2 x \ln (13), we get;

x \ln (2)-2 x \ln (13)=-5 \ln (2)

Taking out the common term x, we have;

x( \ln (2)-2 \ln (13))=-5 \ln (2)

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                          x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}

Thus, the value of x is x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}

6 0
4 years ago
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Mamont248 [21]

Answer:

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Step-by-step explanation:

6 0
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