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2 years ago

Whats equivalent to 3(2x+y)+5y

Mathematics

2 answers:

scZoUnD [109]2 years ago

8 0

Answer:

Step-by-step explanation:

First 3 times 2 it gives you 6

Then you have. (6x+y)+5y

After you solve the values x and y's

Which will give you (6×+5y)

That equals 11x or 11y

gavmur [86]2 years ago

6 0

Answer hi yes is it no way ok it’s ha to be

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The sum of two numbers is 4 and the difference is -6. What is the product of the two numbers?

gladu [14]

Answer: 4

Step-by-step explanation:

the sum of two numbers is 4

the two numbers are 2

2+2=4-6

hope this helps

plz mark brainliest

7 0

2 years ago

A researcher wants to determine whether there is a relationship between age and the number of text messages sent in a given day.

Hatshy [7]

Answer:

$ME= 2.58 \sqrt{\frac{0.8(1-0.8)}{125} +\frac{0.625 (1-0.625)}{120}}= 0.1465$

The best option would be:

d. 0.1465

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for brand 18-25 users

$\hat p_A =\frac{100}{125}=0.8$ represent the estimated proportion for 18-25 users

$n_A=125$ is the sample size

$p_B$ represent the real population proportion for 26-35 users

$\hat p_B =\frac{75}{120}=0.625$ represent the estimated proportion for 26-35 users

$n_B=120$ is the sample size required for Brand B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.