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vodka [1.7K]
3 years ago
9

How do you solve this systems of equations problem 2r +3s=-5 6s=2r

Mathematics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

2r + 3s = - 5 → (1)

6s = 2r → (2) ( divide both sides by 2 ), then

r = 3s

Substitute r = 3s into (1)

2(3s) + 3s = - 5

6s + 3s = - 5

9s = - 5 ( divide both sides by 9 )

s = - \frac{5}{9}

Substitute this value into either of the 2 equations and evaluate for r

Substituting into r = 3s, then

r = 3 × - \frac{5}{9} = - \frac{5}{3}

Solution is r = - \frac{5}{3} and s = - \frac{5}{9}

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