How do you solve this systems of equations problem 2r +3s=-5 6s=2r
1 answer:
Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
2r + 3s = - 5 → (1)
6s = 2r → (2) ( divide both sides by 2 ), then
r = 3s
Substitute r = 3s into (1)
2(3s) + 3s = - 5
6s + 3s = - 5
9s = - 5 ( divide both sides by 9 )
s = -
Substitute this value into either of the 2 equations and evaluate for r
Substituting into r = 3s, then
r = 3 × - = -
Solution is r = - and s = -
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Answer:
Chandra's Average Monthly Expenses are;
1) For Both Jan and Feb are $269
2) For the remaining 10 months each are $244
Step-by-step explanation:
From Chandra's matrix all monthly expenses are all same that is,
Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.
That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.
Therefore, you start by adding up each month total expenses, which are ;
January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886
February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886
March = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
April = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
May = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
June = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
July= $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
August = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
September = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
October = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
November = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
December = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
Therefore Chandra's Average Monthly Expenses are:
1) January & February = =
= 269.4286 to the nearest cent
≅ $269
2) For the remaining 10 month are = =
= 243.5 to the nearest cent
≅ $244
If the pattern continues, so that each term is separated by a distance of 3, then the sequence is given by the recursive rule
From this definition, we can write in terms of
:
and so on, up to
(notice how the subscript on <em>a</em> and coefficient on 3 add up to <em>n</em>)
or