How do you solve this systems of equations problem 2r +3s=-5 6s=2r
1 answer:
Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
2r + 3s = - 5 → (1)
6s = 2r → (2) ( divide both sides by 2 ), then
r = 3s
Substitute r = 3s into (1)
2(3s) + 3s = - 5
6s + 3s = - 5
9s = - 5 ( divide both sides by 9 )
s = -
Substitute this value into either of the 2 equations and evaluate for r
Substituting into r = 3s, then
r = 3 × - = -
Solution is r = - and s = -
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Answer:
Step-by-step explanation:
The equation of line in the form .
y = mx + c
Where m is the slope and c is the y- intercept .
As given
The lines y=3x-1 and y=ax+2 are perpendicular .
Here 3 is slope for equation of line y=3x-1 and a is slope for equation of line
y=ax+2 .
Now by using properties of the perpendicular lines property .
When two lines are perpendicular than slope of one line is negative reciprocal of the other line .
Thus
Therefore